Given that, Nathan shares out 12 sweets, if he gives Yasmin 1 sweet for 3 sweets he buys, Nathan will get 9 sweets.
<h3>How many sweets does Nathan gets?</h3>
Given that, Nathan shares out 12 sweets, he gives Yasmin 1 sweet for 3 sweets he buys.
Let the sweet be represented by x
For each x sweet for Yasmin, Nathan gets 3x sweets
Hence
x + 3x = 12
We solve for x
4x = 12
x = 12/4
x = 3
Hence;
Yasmin gets x sweet = 3
Nathan gets 3x sweets = 3 × 3 = 9
Given that, Nathan shares out 12 sweets, if he gives Yasmin 1 sweet for 3 sweets he buys, Nathan will get 9 sweets.
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Presumably d meanst distance and t means time.
When t = 1, d = 2.5
When t = 3, d = 4
d = mt + b
2.5 = m + b [t = 1]
4.0 = 3m + b [t = 2]
1.5 = 2m [subtract]
m = .75 = slope
b = 1.75 = d-intercept
d = .75t + 1.75
d = 15/4 + 7/4 [t = 5]
d = 22/4 = 5.5 m from sensor
Answer:
1. a= 7, A = 49 degrees
Side A = 7 , Side B = 24, Side C = 25
A= 49 degrees, C = 90 degrees , B=41
2. A= 4, B = 6.9, C=8
A= 22 degrees, B = 68, C= 90
3. A= 7, B = 14.4, C=16
A= 45 , B=45 , C=90
Answer:
The z-score for the 34-week gestation period baby is 0.61
Step-by-step explanation:
The formula for calculating a z-score is is z = (x-μ)/σ,
where x is the raw score,
μ is the population mean
σ is the population standard deviation.
We are told in the question that:
Babies born after a gestation period of 32-35 weeks have a mean weight of 2600 grams and a standard deviation of 660 grams. Also, we are supposing a 34-week gestation period baby weighs 3000grams
The z-score for the 34-week gestation period baby is calculated as:
z = (x-μ)/σ
x = 3000, μ = 2600 σ = 660
z = 3000 - 2600/660
= 400/660
=0.6060606061
Approximately, ≈ 0.61
Answer:
The function for the outside temperature is represented by ![T(t) = 85\º + 15\º \cdot \sin \left[\frac{t-6\,h}{24\,h} \right]](https://tex.z-dn.net/?f=T%28t%29%20%3D%2085%5C%C2%BA%20%2B%2015%5C%C2%BA%20%5Ccdot%20%5Csin%20%5Cleft%5B%5Cfrac%7Bt-6%5C%2Ch%7D%7B24%5C%2Ch%7D%20%5Cright%5D)
, where t is measured in hours.
Step-by-step explanation:
Since outside temperature can be modelled as a sinusoidal function, the period is of 24 hours and amplitude of temperature and average temperature are, respectively:
Amplitude
Mean temperature
Given that average temperature occurs six hours after the lowest temperature is registered. The temperature function is expressed as:
![T(t) = \bar T + A \cdot \sin \left[2\pi\cdot\frac{t-6\,h}{\tau} \right]](https://tex.z-dn.net/?f=T%28t%29%20%3D%20%5Cbar%20T%20%2B%20A%20%5Ccdot%20%5Csin%20%5Cleft%5B2%5Cpi%5Ccdot%5Cfrac%7Bt-6%5C%2Ch%7D%7B%5Ctau%7D%20%5Cright%5D)
Where:
- Mean temperature, measured in degrees.
- Amplitude, measured in degrees.
- Daily period, measured in hours.
- Time, measured in hours. (where t = 0 corresponds with 5 AM).
If , and 
, the resulting function for the outside temperature is:
