9514 1404 393
Answer:
a) BE = 5; DE = 6; EF = 4
b) ∠EFC ≅ ∠DA.F ≅ ∠BDE or <em>b = e = f = i</em>
Step-by-step explanation:
Each short segment is the same length as the marked one it is parallel to.
E is the midpoint of BC, so BE = EC = 5.
ADEF is a parallelogram, so DE = A.F = 6.
D is the midpoint of AB, so AD = DB = 4. ADEF is a parallelogram, so ...
EF = AD = 4
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As we have noted, AB║EF and DE║A.F, so corresponding angles and alternate interior angles are congruent. <em>b = e = f = i</em>
1. Given any triangle ABC with sides BC=a, AC=b and AB=c, the following are true :
i) the larger the angle, the larger the side in front of it, and the other way around as well. (Sine Law) Let a=20 in, then the largest angle is angle A.
ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:

2.

3. m(A) = Arccos(-0.641)≈130°,
4. Remark: We calculate Arccos with a scientific calculator or computer software unless it is one of the well known values, ex Arccos(0.5)=60°, Arccos(-0.5)=120° etc
Answer:
45
Step-by-step explanation:
yes yes i think this is very correct very yes
First move the 2n over to the other side by subtracting it
so
4n=-8
then divide 4n by 4 and do the same to the other side
so
n= -8/4
n= -2
Answer:
it will go up as all the groups will be removed from lower side reducing it's weights