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3 years ago

You find your watch gains 2 minutes in 6 hours. How much will it gain in three days

2 answers:

6 0

There is 24 hours in one day, if you multiply 6 by 4 it equals 24

So 2 minutes x 4 = 8

So the watch gains 8 minutes in 1 day

Now multiply 8 and the days

8 x 3 = 24

So the watch gains 24 minutes in three days

Hope I helped ;)

Nezavi [6.7K]3 years ago

4 0

You have to set up a proportion for this question. First, you have to know how many hours are in 3 days. There are 72 hours in 3 days, so now you can set up your proportion. 2:6 and _:72. You need to find out what 72 divided by 6 is. it is 12, so now you must multiply 12 by 2, and get 24. So, if your watch has gained 2 minutes in 6 hours, than in 3 days, it will have gained 24 minutes.

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The table represents a function what is f(-2)

wolverine [178]

$\bf \begin{array}{ccll}
x&f(x)\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
-6&3\\
-2&\boxed{1}\\
0&4\\
3&-2
\end{array}\qquad \qquad f(\stackrel{x}{-2})\implies x=-2$

8 0

3 years ago

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a country's population in 1990 was 134 million. in 2000 it was a 139 million. estimate the population in 2014 using the exponent

yuradex [85]

F=ir^t

139=134r^10

139/134=r^10

r=(139/134)^(1/10) then:

f=134(139/134)^(t/10) so in 2014, t=24 so

f=134(139/134)^(2.4)

f≈146 million (to nearest million)

Some will say that you have to use the exponential function, but it really gives you the same answer...even for continuous compounding :)...

A=Pe^(kt)

139=134e^(10k)

139/134=e^(10k)

ln(139/134)=10k

k=ln(139/134)/10 so

A=134e^(t*ln(139/134)/10) when t=24

A=134e^(2.4*ln(139/134))

A≈146 million (to nearest million)

The only real reason or advantage to using A=Pe^(kt) is when you start getting into differential equations...

6 0

3 years ago

Find the slope and then write the equation Y=MX+B

timurjin [86]

Answer:

y=2x+15

Step-by-step explanation:

Slope (m) = 20/10 = 2

y-intercept (b) = 15

4 0

3 years ago

In a test of the effectiveness of garlic for lowering cholesterol, 8181 subjects were treated with raw garlic. Cholesterol leve

xz_007 [3.2K]

Answer:

With garlic treatment, the mean change in LDL cholesterol is not greater than 0.

Step-by-step explanation:

The dependent t-test (also known as the paired t-test or paired samples t-test) compares the two means associated groups to conclude if there is a statistically significant difference amid these two means.

In this case a paired t-test is used to determine the effectiveness of garlic for lowering cholesterol.

A random sample of 81 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment.

The hypothesis for the test can be defined as follows:

H₀: With garlic treatment, the mean change in LDL cholesterol is not greater than 0, i.e. d ≤ 0.

Hₐ: With garlic treatment, the mean change in LDL cholesterol is greater than 0, i.e. d > 0.

The information provided is:

$\bar d=0.40\\SD_{d}=16.2\\\alpha =0.01$

Compute the test statistic value as follows:

$t=\frac{\bar d}{SD_{d}/\sqrt{n}}\\\\=\frac{0.40}{16.2/\sqrt{81}}\\\\=0.22$

The test statistic value is 0.22.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

Compute the p-value of the test as follows:

$p-value=P(t_{n-1}>0.22)\\=P(t_{80}>0.22)\\=0.4132$

*Use a t-table.

The p-value of the test is 0.4132.

p-value= 0.4132 > α = 0.01

The null hypothesis was failed to be rejected.

Thus, it can be concluded that with garlic treatment, the mean change in LDL cholesterol is not greater than 0.

3 0

3 years ago

PLEASEEEE HELP!! Which is the graph of y = ⌊x⌋ – 2?

sergiy2304 [10]

The first one
You start at -2 and go up 1 and to the right 1

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2 years ago

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