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Sphinxa [80]
3 years ago
6

What are some ways to describe the relationship between sets of numbers?

Mathematics
1 answer:
Hatshy [7]3 years ago
7 0
Fractions, ratios, ...that's about all I got
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Do these ordered pairs represent a function?<br> (0, 1), (0, 2), (2,3), (4,8)
Aleksandr-060686 [28]

Answer:

No

Step-by-step explanation:

To be a function, each input can only go to one output

0 goes to 1 and 2 so it cannot be a functions

8 0
3 years ago
The distance between two cities is 180km. The distance was covered by a car at the rate of 50km/h, by a bus 45km/h, by a truck a
Gennadij [26K]

Answer:

The speed and time are directly proportional in that the higher the speed the lesser the time and vice versa.

The constant is the total distance which is 180 km

Step-by-step explanation:

Step one:

given data

The distance between the  two cities is 180km

1.The distance was covered by a car at the rate of 50km/h

The time taken will be

velocity= distance/time

time= distance/velocity

time= 180/50

time= 3.6 hours

2.The distance was covered by a bus 45km/h

The time taken will be

velocity= distance/time

time= distance/velocity

time= 180/45

time= 4 hours

3.The distance was covered by a bicycle at 25km/h

The time taken will be

velocity= distance/time

time= distance/velocity

time= 180/25

time= 7.2 hours

7 0
3 years ago
PLS PLS I NEED HELP I HAVE NO TIME I'LL MARK YOU BRAINLIST !!!
Dominik [7]

Answer:

1) y = 5/2x - 3/2

2) y = 2/5x - 4/5

Step-by-step explanation:

1)

(1, 1) and (3, 6)

m = (y2 - y1)/(x2 - x1)

m= (6 - 1)/(3-1)

m= 5/2

m= 5/2

y - y1 = m(x - x1)

y - 1 = 5/2(x - 1)

y - 1 = 5/2x - 5/2

y = 5/2x - 3/2

2)

(2, 0) and (7, 2)

m = (y2 - y1)/(x2 - x1)

m= (2 - 0)/(7 - 2)

m = 2/5

y - y1 = m(x - x1)

y - 0 = 2/5(x - 2)

y = 2/5x - 4/5

5 0
2 years ago
Read 2 more answers
Find the equation of the line that goes through the points (3,8) and (9,16).
Aneli [31]

Answer:

4x-3y+12=0 is required eqn

Step-by-step explanation:

Let, 3,8 be x1,y1

9,16 be x2,y2

Now,

Eqn of st.line is y-y1 = y2-y2/x2-x1 * (x-x1)

y-8 = 16-8/9-3 * (x-3)

y-8 = 4/3*(x-3)

3y-24 = 4x-12

4x-3y+12=0 is required eqn

3 0
3 years ago
1.8.2
VLD [36.1K]

Answer:

5,

4.66

4

-0.97

-3/2

-20

3 0
3 years ago
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