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Sphinxa [80]
3 years ago
6

What are some ways to describe the relationship between sets of numbers?

Mathematics
1 answer:
Hatshy [7]3 years ago
7 0
Fractions, ratios, ...that's about all I got
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Vesna [10]

Answer:

1. Recursive formula: b(n-1)+2

2. Explicit formula: −2n+5

3. -20

4. 2, 11, 20, 29, 38, 47, 56, 65, 74, 83, 92, 101, 110, 119, 128

Step-by-step explanation:

4 0
3 years ago
I need help with 3 and 4
frosja888 [35]

Answer:

Step-by-step explanation:

3) G

Step-by-step explanation:

Q(-1,-1) R(3,1) S(2,-4)

x+2 y+3 translation then rotation 180 (x,y) be (-x,-y)

Q -1+2 -1+3 (1,2) (-1,-2)

R 3+2 1+3 (5,4) (-5,-4)

S 2+2 -4+3 (4,-1)

4 0
4 years ago
The metal in a penny is worth about 0.505 cent . How much cents is this written as a fraction?\
Ratling [72]
0.505 means 505 * 0.001, or 505 * 1/1000. This is equivalent to 505/1000, or 101/200.
8 0
3 years ago
Jesse estimates the weight of her cat to be 10 pounds. The actual weight of the cat is 13.75.Find the percent of error.
horrorfan [7]

Answer:

The percent error is 27.27%

Step-by-step explanation:

I did this by using the formula actual-estimated value/actual value

In this case it would be 3.75/13.75 and I got .2727 and then had to multiply by 100 (to find percent not decimal form) and got 27.27%

5 0
4 years ago
The number of accidents per week at a hazardous intersection varies with mean 2.2 and standard deviation 1.4. This distribution
ankoles [38]

Answer:

a) Normal Distribution

b) 0.146

c) 0.070

Step-by-step explanation:

We are given the following information in the question:

The number of accidents per week at a hazardous intersection varies with mean 2.2 and standard deviation 1.4

a) \bar{x}: mean number of accidents per week at the intersection during a year (52 weeks)

According to central limit theorem, as the sample size becomes larger, the distribution of mean approaches a normal distribution.

Since we have a large sample, the approximate distribution of \bar{x} is a normal distribution with

\text{Mean} = 2.2\\\text{Standard Deviation} = \displaystyle\frac{\sigma}{\sqrt{n}} = \frac{1.4}{\sqrt{52}} = 0.19

b) P(mean is less than 2)

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(x > 610)

P( \bar{x} < 2) = P( z < \displaystyle\frac{2 - 2.2}{0.19}) = P(z < -1.052)

Calculation the value from standard normal z table, we have,  

P(\bar{x} < 2) = 0.146

c) P(fewer than 100 accidents at the intersection in a year)

P(x < 100)

P( \bar{x} < \frac{100}{52}) =P(\bar{x} < 1.92) =P(z < \displaystyle\frac{1.92 - 2.2}{0.19}) = P(z < -1.473)

Calculation the value from standard normal z table, we have,  

P(x

7 0
3 years ago
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