Whats 2x+5=7<br><br> I really need help quick!

Do you support LGBTQ<br> people???

Andrew [12]

Answer:

YES

Step-by-step explanation:

YES

4 0

3 years ago

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Find the domain of y=2/3x-1 if the range is {-3, -1, 7, 17}.

White raven [17]

<h3>Answer: The domain is {-3, 0, 12, 27}</h3>

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Explanation:

First solve for x to get

y = (2/3)x - 1

y+1 = (2/3)x

(2/3)x = y+1

x = (3/2)*(y+1)

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Now plug the values given into y. Do so one at a time. Lets plug in y = -3

x = (3/2)*(y+1)

x = (3/2)*(-3+1)

x = 1.5*(-2)

x = -3

So the domain value x = -3 corresponds to the range value y = -3.

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Repeat for y = -1

x = (3/2)*(y+1)

x = (3/2)*(-1+1)

x = 1.5*0

x = 0

The domain value x = 0 corresponds to the range value y = -1

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Repeat for y = 7

x = (3/2)*(y+1)

x = (3/2)*(7+1)

x = 1.5*8

x = 12

The domain value x = 12 corresponds to the range value y = 7

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Repeat for y = 17

x = (3/2)*(y+1)

x = (3/2)*(17+1)

x = 1.5*18

x = 27

The domain value x = 27 corresponds to the range value y = 17

8 0

3 years ago

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Solve 2x+3y=26 and x+4y=24 using elimination

kogti [31]

The answer is (6.4, 4.4).

3 0

3 years ago

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Which of the following should not be used as a guideline for making a purchase?

mrs_skeptik [129]

Answer:

Step-by-step explanation:

3 0

3 years ago

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I need help! (HAPPY MLK DAY!!!)

olga2289 [7]

The slope and length of the given sides of the quadrilateral can be

found by using the coordinates of the vertices.

Correct responses:

$Slope \ of \ \overline{IJ} = \underline{-\dfrac{7}{6} }$ , Length of $\overline{IJ}$ = $\underline{\sqrt{85} }$

$Slope \ of \ \overline{JK} = \underline {-\dfrac{2}{9}}$ , Length of $\overline{JK}$ = $\underline{\sqrt{85} }$

$Slope \ of \ \overline{KL} = \underline{-\dfrac{7}{6} }$ , Length of $\overline{KL}$ = $\underline{\sqrt{85}}$

$Slope \ of \ \overline{LI} = \underline{ -\dfrac{2}{9} }$ , Length of $\overline{LI}$ = $\underline{\sqrt{85} }$

<h3>Methods used to find the slope and length of a line</h3>

The given coordinates of the vertices are;

K(-7, 0), J(2, -2), I(8, -9), L(-1, -7)

$Slope = \mathbf{\dfrac{y_2 - y_1}{x_2 - x_1}}$

$Length \ of \ line = \mathbf{ \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}}$

Therefore;

$Slope \ of \ \mathbf{\overline{IJ}} = \dfrac{-2 - (-9)}{2 - 8} = \dfrac{7}{-6} = \underline{ -\dfrac{7}{6}}$

$Length \ of \ \mathbf{\overline{IJ}} = \sqrt{(2 - 8)^2 + (-2 - (-9))^2} = \underline{\sqrt{85}}$

$Slope \ of \ \mathbf{\overline{JK}} = \dfrac{0 - (-2)}{-7 - 2} = \dfrac{2}{-9} = \underline{-\dfrac{2}{9}}$

$Length \ of \ \mathbf{\overline{JK}} = \sqrt{(-7 - 2)^2 + (0 - (-2))^2} = \underline{ \sqrt{85}}$

$Slope \ of \ \mathbf{\overline{KL}} = \dfrac{0 - (-7)}{-7 - (-1)} = \dfrac{7}{-6} = \underline{ -\dfrac{7}{6}}$

$Length \ of \ \mathbf{\overline{KL} }= \sqrt{(-7 - (-1))^2 + (0 - (-7))^2} =\underline{ \sqrt{85}}$

$Slope \ of \ \mathbf{\overline{LI}} = \dfrac{(-9 - (-7))}{(8 - (-1))} = \dfrac{-2}{9} = \underline{-\dfrac{2}{9}}$

$Length \ of \ \mathbf{\overline{LI}} = \sqrt{(8 - (-1))^2 + (-9 - (-7))^2} = \underline{\sqrt{85}}$

Learn more about finding the slope and length of a line here:

brainly.com/question/11612395

brainly.com/question/14039630

5 0

3 years ago

Whats 2x+5=7 I really need help quick!