1. M is the midpoint of LN and O is the midpoint of NP. This makes the triangle MNO equal to half of LNP. Then you can get this equation
MO= (1/2) LP
If you insert MO = 2x +6 and LP = 8x – 20 the calculation would be:
2x+6= (1/2)( 8x-20)
2x+6= 4x-10
2x-4x= -10 - 6
-2x= -16
x=8
2. Centroid is the point that intersects with three median lines of the triangle. The centroid should divide the median lines into 1:2 ratio. In AC lines, A located in the base so A.F:FC would be 1:2
Then, the answer would be:
A.F= 1/(1+2) * AC
A.F= 1/3 * 12= 4
FC= 2/(1+2) * AC
FC= 2/3 * 12= 8
3. Since
∠BAD=∠DAC
∠ABD=∠ACD
AD=AD
The triangle ABD and ACD are similar. You can get this equation
BD=DC
x+8= 3x+12
x-3x= 12-8
-2x=4
x=-2
DC=3x+12= 3(-2) +12= 6
4. Orthocenter made by intersection of triangle altitude
A
BC lines slope would be (-4)-(-1)/1-4= -3/-3= 1. The altitude line slope would be -1, the function would be:
y=-x +a
0= 1+a
a=-1
y=-x-1
B
AC lines slope would be (-4)-(-1)/1-0= -3. The altitude line slope would be 1/3, the function would be:
y=1/3x+a
-1=1/3(4)+a
a=-7/3
y=1/3x - 7/3
C
BC lines slope would be (-1)-(-1)/4 = 0/4.
The line would be
0=x+a
a=-1
0=x-1
x=1
y=-x-1 = 1/3x-7/3
-x-(1/3x)=-7/3 +1
-4/3x= -4/3
x=1
y=-x-1
y=-1-1= -2
The orthocenter would be (1,-2)
5.
a. Circumcenter: the intersection of perpendicular bisector lines<span>
b. Incenter: the intersection of bisector lines
c. Centroid: </span>the intersection of median lines<span>
d. Orthocenter: </span>the intersection of altitude lines
Answer:
1. Rate needed 9/6; Unit rate is 1.5/1; 1.5 cans of white paint are needed for each can of blue.
2. rate needed = 12/6; unit rate = 2/1; Need 2 cups of water for every scoop of fruit mix.
3. 70 minutes
Step-by-step explanation:
1. Set up a ratio
3white/2blue = xwhite/6blue
3/2 = x/6
cross multiply 2x = 18; x = 9
rate needed = 9/6
Unit rate is 1.5/1 (divide 3 by 2 or 9 by 6 to get unit rate_
2. 3/1.5 = x/6
1.5x = 18; x = 12
rate needed = 12/6
unit rate = 2/1
3. Set up a ratio.
3.5/.25 ( 1/4=.25)
3.5/.25 = x/5
.25x = 3.5(5)
.25x = 17.5
x = 70 minutes
Answer:
x=6 . m<PQS=82 m<SQR=61 :)
Step-by-step explanation:
(13x+4) + (10x-1) = 141
combine like terms
23x+3=141
subtract 3 from both sides
23x=138
divide both sides by 23
x=6
substitute x into both original equations
m<PQS=13(6)+4
m<PQS=78+4
m<PQS= 82
m<SQR=10(6)+1
m<SQR=60+1
M<SQR=61
Polygon HJKL has vertices H(-3, 4), J(2, 6), K(2, 1), and L(-3, -1). What are the slopes of sides HJ, JK, KL, and LH and how wou
aleksklad [387]
<span> the slopes of sides HJ, JK, KL, and LH and how would you classify HJKL?</span>