Answer:
Step-by-step explanation:
GIVEN: A car was sold 
standard washed in a day , which was 
of their total sales for that day.
TO FIND: Total amount of washes that the car wash sold that day.
SOLUTION:
Let the total sales of car washes sold for that day 
total number of standard car washes sold 
As, total standard car washes sold are of total sales in a day
putting value in equation
Hence the total number of car washes sold that day are
the answer should be letter A
the difference of 3.4 and 1.25 = 2.15
Now you know that there will be 2 whole blocks and .15 of a block
.15 is equal to 3/20 which is equal to 15/100.
So you will have 2 whole blocks and 15/100 of a blocks. So the answer is A
Scientific notation is used to express very large or very small values.
Numbers in scientific notation are written in the form of
m × 10 to the power of n
For example:
500 is written as 5 x 10^2 where:
500 = 5 x 10 x 10
Now, let's consider 7 x 10^3:
Following the same procedure:
7 x 10^3 = 7 x 10 x 10 x 10 = 7000
The pattern can be written as:
7 x 10^3 = 7 x 10 x 10^2
= 70 x 10^2
= 70 x 10 x 10^1
= 700 x 10
= 7000
Answer:
y = 100 - 8(n - 1)
Step-by-step explanation:
I. if n = 1 or 1st year = 100 - 8(1-1) is 100
if n = 2 or 2nd year = 100 - 8(2-1) is 92
if n = 3 or 3rd year = 100 -8(3-1) is 84
Hope it'll help.
Answer:
<u>Cost = 25 + 50h</u>
cost for 8 hours of work = $425
cost for 10 hours of work = $525
Step-by-step explanation:
The question is as following:
A plumber charges $25 for a service call plus $50 per hour of service write an equation to represent the cost of hiring this plumber.
what will be the cost for 8 hours of work? 10 hours of work?
=======================================================
A plumber charges $25 for a service call plus $50 per hour
<u>Cost = 25 + 50h</u>
Where h is the number of hours of service
8 hours of work: h = 8
Substitute with h = 8 at the equation of cost
<u>Cost = 25 + 50* 8 = $425</u>
10 hours of work: h = 10
Substitute with h = 10 at the equation of cost
<u>Cost = 25 + 50 * 10 = $525</u>
