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kykrilka [37]
3 years ago
9

A 1100- car is held in place by a light cable on a very smooth (frictionless) ramp, as shown in the figure (Figure 1) . The cabl

e makes an angle of 31.0 above the surface of the ramp, and the ramp itself rises at 25.0 above the horizontal.
Mathematics
1 answer:
Lunna [17]3 years ago
7 0

So far i have determined the following equations from the my force body diagrams. T(cos(31)) - mg(sin(25)) = 0 N - (mg(cos(25)) + (T(sin(31))) = 0 to solve for tension you rearrange the first equation to get T(cos(31)) = mg(sin(25)) so if you solve for the horizontal component of gravity you will be able to determine the tension of the string. i have tried my following answer (which comes out to 1426N) but i am incorrect. if anyone can please point out what i am missing i would be really appreciate it.

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The cost for a pack of 18 pencils is $3.24. Find the unit price in dollars per pencil. If necessary, round your answer to the ne
nexus9112 [7]

Answer:

$0.18 per pencil.

Step-by-step explanation:

"Dollars per unit" means that you take the dollar amount and divide it by the amount of pencils, so you get 3.24/18, or .18.

4 0
3 years ago
What is the approximate area of a sector given O= 56 degrees with a diameter of 12m?​
jeyben [28]

Area of sector is 17.584 meters

<em><u>Solution:</u></em>

Given that we have to find the approximate area of a sector given O= 56 degrees with a diameter of 12m

Diameter = 12 m

Radius = Diameter / 2 = 6 m

An angle of  56 degrees is the fraction \frac{56}{360} of the whole rotation

A sector of a circle with a sector angle of 56 degrees is therefore also the fraction \frac{56}{360} of the circle

The area of the sector will therefore also be  \frac{56}{360} of the area

\text{ sector area } = \frac{56}{360} \times \pi r^2\\\\\text{ sector area } = \frac{56}{360} \times 3.14 \times 6^2\\\\\text{ sector area } = 17.584

Thus area of sector is 17.584 meters

3 0
3 years ago
The circle graph below shows the Johnson family budget for one month.
IceJOKER [234]
Answer
1/3

hope this helps have a nice day:)
4 0
3 years ago
Read 2 more answers
At a farm, the average number of chickens, ducks, rabbits and sheep is 315 per type of animal. The average number of chickens, d
Greeley [361]

The average number of chickens, ducks, rabbits and sheep = 315 per type of animal.

The average number of chickens, ducks and rabbits = 320 per type of animal.

The number of sheep is 60 more than the number of rabbits.

Let us assume number of rabbits = x.

Number of sheep is 60 more than number of rabbits, that is = x+60.

There are half as many ducks as there are rabbits.

Therefore, number of ducks = x/2.

Let us assume number of chickens = y.

Adding  number of chickens, number of rabbits, number of sheep and number of ducks and dividing by 4 (because those are four types of animal).

\frac{y+x+x+60+x/2}{4}  = 315

Multiplying both sides by 4, we get

y+x+x+60+x/2 = 1260

Subtracting 60 from both sides

y+x+x+60-60+x/2 = 1260-60

y+x+x+x/2 = 1200.

Combining like terms .

y + 5x/2 = 1200

Multiplying both sides by 2, we get

<em>2y +5x = 2400  ------------equation (1)</em>

Adding  number of chickens, number of rabbits and number of ducks and dividing by 3 (because those are three types of animal).

\frac{y+x+60+x/2}{3}  = 320

Multiplying both sides by 3, we get

y+x+60+x/2 = 960

Subtracting 60 from both sides

y+ x+x/2 = 900

Combining like terms .

y+ 3x/2 = 900

Multiplying both sides by 2, we get

<em>2y+3x = 1800 --------------------equation (2)</em>

Multiplying first equation by 3 and second equation by -5, we get

(2y +5x = 2400 ) * 3   => 6y +15x = 7200

(2y+3x = 1800) *-5      =>

Adding

6y +15x = 7200

-10x + -15x = -9000.

_________________

-4y = -1800.

Dividing both sides by -4, we get

y=450.

<h3>Therefore, number of chickens are  450 there at the farm.</h3>


7 0
3 years ago
What is the sum of 173, 32, 4, and 1,032?
Elodia [21]
1241
173+32+4+1032=1241
3 0
3 years ago
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