Range of the function f(x) = -x^2 - 5
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The length of the line segment BC is 31.2 units.
<h2>Given that</h2>Triangle ABC is shown.
Angle ABC is a right angle.
An altitude is drawn from point B to point D on side AC to form a right angle.
The length of AD is 5 and the length of BD is 12.
<h3>We have to determine</h3>What is the length of Line segment BC?
<h3>According to the question</h3>The altitude of the triangle is given by;
Where x is DC and y is 5 units.
Then,
The length DC is.
Squaring on both sides
Considering right triangle BDC, use the Pythagorean theorem to find BC:
Hence, the length of the line segment BC is 31.2 units.
To know more about Pythagoras Theorem click the link given below.
In calculus, we use derivatives to find the instantaneous rate of change at any point on a graph. To find the average rate of change, we just find the slope of the secant line that intercepts two points on the graph.
We find slope with the following equation:
In this case, we are looking for the slope from x = -1 to x = 1. We have both x values, so next we need the y values.
F(-1) = (-1)^2 - (-1) - 1 = 1
F(1) = (1)^2 - (1) - 1 = -1
Now plug in the x and y values to find the slope:
The answer is -1.
We find slope with the following equation:
In this case, we are looking for the slope from x = -1 to x = 1. We have both x values, so next we need the y values.
F(-1) = (-1)^2 - (-1) - 1 = 1
F(1) = (1)^2 - (1) - 1 = -1
Now plug in the x and y values to find the slope:
The answer is -1.