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rodikova [14]
3 years ago
8

One factor of 7x2 + 33x – 10 is

Mathematics
1 answer:
stiv31 [10]3 years ago
6 0

7x^{2} +33x-10=0

\implies 7x^{2} +35x-2x-10=0\\\implies7x(x+5)-2(x+5)=0\\\implies (7x-2)(x+5)=0

7x - 2 = 0\\\implies \boxed{\bold{x = \frac{2}{7} }}

x+5=0\\\implies \boxed{\bold{x=-5}}

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I really suck at math. please help =)
FrozenT [24]
Check the picture below.

6 0
4 years ago
A library contains 2,000 books. There are 3 times as many
julsineya [31]

Answer:

500 de no ficcion y 1500 de ficcion

Step-by-step explanation:

si tomamos que hay 2000 libros hay que buscar un numero que multiplicado 3 veces por si mismo nos de 2000, como ya tenemos el 500 que seria los libros de no ficcion, ahora tenemos que e si al multiplicarlo por 3 veces nos da los 1500 que nos falta para completar 2000

500 + 1500 = 2000

6 0
3 years ago
Why is one called the multiplicative identity? HELP!!!!
Serjik [45]
The Multiplicative Identity Property. This means that you can multiply 1 to any number... and it keeps its identity! The number stays the same!
7 0
4 years ago
A simple random sample of 90 is drawn from a normally distributed population, and the mean is found to be 138, with a standard d
bagirrra123 [75]

The 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C:  [130.10, 143.90]

<h3>
How to find the confidence interval for population mean from large samples (sample size > 30)?</h3>

Suppose that we have:

  • Sample size n > 30
  • Sample mean = \overline{x}
  • Sample standard deviation = s
  • Population standard deviation = \sigma
  • Level of significance = \alpha

Then the confidence interval is obtained as

  • Case 1: Population standard deviation is known

\overline{x} \pm Z_{\alpha /2}\dfrac{\sigma}{\sqrt{n}}

  • Case 2: Population standard deviation is unknown.

\overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}

For this case, we're given that:

  • Sample size n = 90 > 30
  • Sample mean = \overline{x} = 138
  • Sample standard deviation = s = 34
  • Level of significance = \alpha = 100% - confidence = 100% - 90% = 10% = 0.1 (converted percent to decimal).

At this level of significance, the critical value of Z is: Z_{0.1/2} = ±1.645

Thus, we get:

CI = \overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}\\CI = 138 \pm 1.645\times \dfrac{34}{\sqrt{90}}\\\\CI \approx 138 \pm 5.896\\CI \approx [138 - 5.896, 138 + 5.896]\\CI \approx [132.104, 143.896] \approx [130.10, 143.90]

Thus, the 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C:  [130.10, 143.90]

Learn more about confidence interval for population mean from large samples here:

brainly.com/question/13770164

3 0
2 years ago
List 0.5 1/5 0.35 12/25 4/5 from least to greatest
Anika [276]
One way is to make them all decimals or all fractions:

.5   .2  .35  .48  .80  are the numbers above changed to decimals.
I will make them the same length (two digit past the decimal point) to compare
.50   .20  .35  .48 and .80

Now it is easy to put them in order

.2  .35  .48   .5  and .80

Let's put them into all fractions

5/10   1/5   35/100   12/25 and 4/5

Instead of finding a common denominator let's try this:
Think of them as test scores - the person who got 1 out 5 did the worst
Next came the person who got only 35 out of 100 - they only did better than the one above (1/5)
12/25 is almost 1/2 but a little below half the questions right
5/10 is exactly half the questions right (so it is bigger than 12/25 by a little).
4/5 is the best score (and the only one who passed).
So 1/5, 35/100, 12/25, .5 and 4/5 are in order least to greatest and match the answer above in bold.
3 0
4 years ago
Read 2 more answers
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