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Veseljchak [2.6K]
3 years ago
12

What is the next letter in the sequence A Z B Y C X D

Mathematics
2 answers:
nalin [4]3 years ago
5 0
The answer is w !!!!!
Eduardwww [97]3 years ago
5 0
W ..... because it is going backwards ZYXW then forward ABCD 
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The differenceof a minus 3 divided by 3
Vika [28.1K]

Answer:

The difference of a minus 3 divided by 3 is - 1.

Step-by-step explanation:

-3/3= - 1

Hope it's helpful.

4 0
3 years ago
Someone help me pleaseeee
Whitepunk [10]

Answer:

you have to add all the angles including 'x' which is equals to 180°.

The process is

99+49+x=180

148+x=180

x=180-148

x=32.

8 0
3 years ago
The length of a rectangle is 3 inches shorter than its width. The perimeter of the rectangle is 50 inches.
CaHeK987 [17]

Answer: Alright the first one is w(w-3) = 50 .. and the second one is 5. 73 and the last one is 2 ( w - 3) + 2w = 50 I think

Step-by-step explanation:

I think these are the answers but choose what You think. make Your best guest good luck

5 0
2 years ago
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AVprozaik [17]
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8 0
3 years ago
Conditional Distribution, Marginal Distribution, Joint Distribution. <br> What’s the difference?
lutik1710 [3]

Explanation:

Marginal distribution: This distribution gives the probability for each possible value of the Random variable ignoring other random variables. Basically, the values of other variables is not considered in the marginal distribution, they can be any value possible. For example, if you have two variables X and Y, the probability of X being equal to a value, lets say, 4, contemplates every possible scenario where X is equal to 4, independently of the value Y has taken. If you want the probability of a dice being a multiple of 3, you are interested that the dice is either 3 or 6, but you dont care if the dice is even or odd.

Conditional distribution: This distribution contrasts from the previous one in the sense that we are restricting the universe of events to specific condition for other variable, making a modification of our marginal results. If we know that throwing a dice will give us a result higher than 2, then to in order to calculate the probability of the dice being a multiple of 3 using that condition, we have two favourable cases (3 and 6) from 4 total possible results (3,4,5 and 6) discarding the impossible values (1 and 2) from this universe since they dont match the condition given (note that the restrictions given can also reduce the total of favourable cases).

The joint distribution calculates the probabilities for two different events (related to two different random variables) occuring simultaneously. If we want to calculate the joint probability of a dice being multiple of 3 and greater than 2 at the same time, our possible cases in this case are 3 and 6 from 6 possible results. We are not discarding 1 or 2 as possible results because we are not assuming, that the dice is greater than 2, that is another condition that we should met in the combination of events.

3 0
3 years ago
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