write an equation in point-point form for the line through the given point with the givedescribe how the graph of y | x| -4 is l
ike the graph of y= |x| and how it is different. slope. (-3,-7); m=-6/5
1 answer:
a) The point-slope form of the equation of a line through point (h, k) with slope m is
y - k = m(x - h)
In point-slope form, the equation of the line through (-3, -7) with slope -6/5 is
y + 7 = (-6/5)(x + 3)
b) The graph of
y = |x|-4
represents a translation downward 4 units of the graph of
y = |x|
It retains the same general shape and axis of symmetry, but will have two (2) x-intercepts instead of one (1).
y - k = m(x - h)
In point-slope form, the equation of the line through (-3, -7) with slope -6/5 is
y + 7 = (-6/5)(x + 3)
b) The graph of
y = |x|-4
represents a translation downward 4 units of the graph of
y = |x|
It retains the same general shape and axis of symmetry, but will have two (2) x-intercepts instead of one (1).
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Answer:
b)
Step-by-step explanation:
A is invertible if and only if det(A)≠0. Let's compute the determinant of A and find the values k for which it is nonzero.
Using Sarrus's rule, we obtain that
Note that the determinant is a quadratic equation on k, which can be factored as above.
Now the determinant is only zero if k=5 or k=2 (the zeroes of the quadratic polynomial). Therefore, if k≠2,5 the determinant is nonzero so A is invertible.