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Ghella [55]
3 years ago
14

The answers on how I do these problems the correct way

Mathematics
1 answer:
dimulka [17.4K]3 years ago
8 0

Step-by-step explanation:

so what you need to do is answer the questions with () and then do the other part

You might be interested in
Write the equation of a piecewise function with a jump discontinuity at x =3. Then, determine which step of the 3-step test for
seraphim [82]

Answer:

Here's a possible example:

Step-by-step explanation:

f(x) =\begin{cases} x & \quad x < 3\\x+3 & \quad x \geq 3\\\end{cases}

Each piece is linear, so the pieces are continuous by themselves.

We need consider only the point at which the pieces meet (x = 3).

\displaystyle \lim_{x \longrightarrow 3^{-}} f(x) = \lim_{x \longrightarrow 3^{-}} x = 3\\\\\displaystyle \lim_{x \longrightarrow 3^{+}} f(x) = \lim_{x \longrightarrow 3^{+}} x+3 = 6\\\\f(3) = x + 3 = 6\\\\\displaystyle \lim_{x \longrightarrow 3^{-}} f(x) \neq f(3)

The left-hand limit does not equal ƒ(x), so there is a jump discontinuity at x =3.

5 0
3 years ago
Find the volume of a right circular cone that has a height of 11.8 ft and a base with a radius of 16 ft. Round your answer to th
andreyandreev [35.5K]

Answer:

3161.8 cubic foot

Step-by-step explanation:

V = 1/3BH = 1/3πr²H

V = 1/3 x 3.14 x 16² x 11.8 = 3161.77

4 0
3 years ago
A rectangle field has an area of 300 square meters and a perimeter of 80 meters. what are the length and width of the field?
Yakvenalex [24]
By definition the area of a rectangle is:
 A = w * l
 The perimeter is:
 P = 2w + 2l
 Where,
 w: width
 l: long
 Substituting values:
 300 = w * l
 80 = 2w + 2l
 Solving the system of equations we have:
 l = 30 m
 w = 10 m
 Answer:
 
The length and width of the field are:
 
l = 30 m
 
w = 10 m
6 0
3 years ago
Solve forp. (1 point)<br>3(p+ 4) =p​
NeX [460]

Answer:

p = -6

Step-by-step explanation:

1) Distribute 3 through the parenthesis {3p + 12 = p}

2) Subtract 12 from each side {3p = p - 12}

3) Subtract p from each side {2p = -12}

4) Divide each side by 2 {p = -6}

5 0
3 years ago
Alexander has nickels, dimes, and quarters in the ratio of 2:1:8, if 40 of Alexander's coins are quarters, how many nickels and
ch4aika [34]

Answer:

He has 10 nickels and 5 dimes

Step-by-step explanation:

We can take advantage of the ratio by dividing 40 by 8, giving us that every 1 in the ratio = 5. So we can multiply 2 x 5 = 10 and 1 x 5 = 5.

Hope this Helps!

4 0
2 years ago
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