Answer: well, C is definitely correct so we can knock that off the board. D i am not so sure about considering that is the most impotant thing in trade so, the and would be D.

hope this helped you...

Step-by-step explanation:

7 0

2 years ago

In right triangle PQR , PQ=12 cm and QR=5cm .What is cos R?

Juliette [100K]

Answer:

cosR = $\frac{5}{13}$

Step-by-step explanation:

assuming the right triangle has ∠ Q = 90° with legs 5 and 12

then this is a 5- 12- 13 right triangle with hypotenuse PR = 13 cm

then

cosR = $\frac{adjacent}{hypotenuse}$ = $\frac{QR}{PR}$ = $\frac{5}{13}$

7 0

1 year ago

the figure shown consists of a triangle resting on a square of side 5 cm. the triangle has a height of 4 cm. what is the total a

aniked [119]

Because its a square all its sides are 5cm
So area of square is 5x5=25cm^2
Triangle is 5x4= 20
20/2 is 10cm^2
25+10=35cm^2

4 0

2 years ago

(-1) + (-1) + (-1) + (-1) + ... 500 times =(a) 500(b) 1(c) -1(d) -500​

(-1) + (-1) + (-1) + (-1) + ... 500 times =(a) 500(b) 1(c) -1(d) -500