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3 years ago

Your salary is $65,788. If you work fifty 40-hour weeks in a year, what is your hourly wage?

Mathematics

1 answer:

Dahasolnce [82]3 years ago

7 0

Answer:

$31.63 per hour

Step-by-step explanation:

$31.63 per hour

40 hour weeks × 52 weeks = 2080 hours

65,788/2080= 31.63

hope this helped,brainliest?

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What is the number name?<br> 5.789

My name is Ann [436]

Answer:

Step-by-step explanation:

5.7 is five and 7 tenths and you keep moving up

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3 years ago

A shelter has enough food to feed an average of 80 hungry people a day for 14 days. If an average of 32 people are at the shelte

egoroff_w [7]

Multiply 80 by 14 to get how many total people they can feed.

80 times 14 is 1120.

Now, divide 1120 by 32 to get how many days the food will last if 32 people come every day.

1120/32 = 35.

The answer is B, 35 days

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4 years ago

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#7) Solve 8c - 3c + 3 = 13.

nordsb [41]

Hello!

$\large\boxed{c = 2}$

8c - 3c + 3 = 13

Begin by combining like terms:

5c + 3 = 13

Subtract 3 from both sides:

5c + 3 - 3 = 13 - 3

5c = 10

Divide both sides by 5:

5c/5 = 10/5

c = 2.

6 0

3 years ago

PLEASE HELP ILL GIVE YOU

alexdok [17]

Answer: No she cannot cover it

Step-by-step explanation:

1yd² = 1296in²

16 x 11 x 9 = 1584in²

1296in² < 1584in²

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3 years ago

Consider two independent tosses of a fair coin. Let A be the event that the first toss results in heads, let B be the event that

aliina [53]

Answer with Step-by-step explanation:

We are given that two independent tosses of a fair coin.

Sample space={HH,HT,TH,TT}

We have to find that A, B and C are pairwise independent.

According to question

A={HH,HT}

B={HH,TH}

C={TT,HH}

$A\cap B=$ {HH}

$B\cap C$ ={HH}

$A\cap C$ ={HH}

P(E)= $\frac{number\;of\;favorable\;cases}{total\;number\;of\;cases}$

Using the formula

Then, we get

Total number of cases=4

Number of favorable cases to event A=2

$P(A)=\frac{2}{4}=\frac{1}{2}$

Number of favorable cases to event B=2

Number of favorable cases to event C=2

$P(B)=\frac{2}{4}=\frac{1}{2}$

$P(C)=\frac{2}{4}=\frac{1}{2}$

If the two events A and B are independent then

$P(A)\cdot P(B)=P(A\cap B)$

$P(A\cap)=\frac{1}{4}$

$P(B\cap C)=\frac{1}{4}$

$P(A\cap C)=\frac{1}{4}$

$P(A)\cdot P(B)=\frac{1}{2}\cdot \frac{1}{2}=\frac{1}{4}$

$P(B)\cdot P(C)=\frac{1}{4}$

$P(A)\cdot P(C)=\frac{1}{4}$

$P(A)\cdot P(B)=P(A\cap B)$

Therefore, A and B are independent

$P(B)\cdot P(C)=P(B\cap C)$

Therefore, B and C are independent

$P(A\cap C)=P(A)\cdot P(C)$

Therefore, A and C are independent.

Hence, A, B and C are pairwise independent.

6 0

3 years ago