The missing value is 12 in a system of equations with infinitely many solutions conditions.
It is given that in the system of equations there are two equations given:
It is required to find the missing value in the second equation.
<h3>What is a linear equation?</h3>
It is defined as the relation between two variables if we plot the graph of the linear equation we will get a straight line.
We have equations:
Let's suppose the missing value is 'Z'
We know that the two pairs of equations have infinitely many solutions if and if they have the same coefficients of variables and the same constant on both sides.
From equation (1)
(multiply both the sides by 3)
...(3)
By comparing the equation (2) and (3), we get
M = 12
Thus, the missing value is 12 in a system of equations with infinitely many solutions conditions.
Learn more about the linear equation.
brainly.com/question/11897796
<h3>Answer:</h3>
It depends:
- 4 if she starts at 4
- 5 if she starts at 0
<h3>Explanation:</h3>
Louise needs to end up a total of 5 times 4 away from zero.
If she starts at 4, which is 1 times 4, then she needs to jump 4 more times, to 2, 3, 4, 5 times 4.
If she starts at 0, then she needs to jump 5 times to 1, 2, 3, 4, 5 times 4. (The values at the end of each jump will be {4, 8, 12, 16, 20}.)
Answer:
Step-by-step explanation:
The area of the shape is the sum of three sections
<u>1. Rectangle</u>
<u>2. Bigger semicircle</u>
- A = 1/2π(14/2)² = 76.96 ≈ 77 in² (rounded)
<u>3. Smaller semicircle</u>
- A = 1/2π(5/2)² = 9.8174 ≈ 10 in² (rounded)
<u>Total area:</u>
Answer:
Step-by-step explanation:
Let, 
= y
sin(y) = 
---------(1)
cos(y) = 
= 
= 
Therefore, from equation (1),
Or ![\frac{d}{dx}[\text{sin}^{-1}(\frac{x}{6})]=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%5B%5Ctext%7Bsin%7D%5E%7B-1%7D%28%5Cfrac%7Bx%7D%7B6%7D%29%5D%3D%5Cfrac%7B1%7D%7B6%5Csqrt%7B1-%5Cfrac%7Bx%5E2%7D%7B36%7D%7D%7D)
At x = 4,
![\frac{d}{dx}[\text{sin}^{-1}(\frac{4}{6})]=\frac{1}{6\sqrt{1-\frac{4^2}{36}}}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%5B%5Ctext%7Bsin%7D%5E%7B-1%7D%28%5Cfrac%7B4%7D%7B6%7D%29%5D%3D%5Cfrac%7B1%7D%7B6%5Csqrt%7B1-%5Cfrac%7B4%5E2%7D%7B36%7D%7D%7D)
![\frac{d}{dx}[\text{sin}^{-1}(\frac{2}{3})]=\frac{1}{6\sqrt{1-\frac{16}{36}}}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%5B%5Ctext%7Bsin%7D%5E%7B-1%7D%28%5Cfrac%7B2%7D%7B3%7D%29%5D%3D%5Cfrac%7B1%7D%7B6%5Csqrt%7B1-%5Cfrac%7B16%7D%7B36%7D%7D%7D)
Must do multiplication first....
-2/5 - 3/7 x 7/10
-2/5 - 21/70 (I'll reduce 21/70)
-2/5 - 3/10
Now you have to find a common denominator and subtract
-35/50 = -7/10......is what I get
