Answer:
<h3>
(2x - 1) 4</h3>
STEP
1
:
Equation at the end of step 1
((((16•(x4))-(32•(x3)))+(23•3x2))-8x)+1
STEP
2
:
Equation at the end of step
2
:
((((16•(x4))-25x3)+(23•3x2))-8x)+1
STEP
3
:
Equation at the end of step
3
:
(((24x4 - 25x3) + (23•3x2)) - 8x) + 1
The distance between the 2 points is at the point (0,3). Did I answer your question?
A should equal to -3 or -4 depending on whether what the equation is.
For example, if it's (1/9)^(a+1)=81^(a+1) x 27^(2-a), then the answer is -4.
But if it's the other way stated above, then it should be -3.
Hope this helps.
The equation of tangent to the circle
at the point (-6,8) is -6x+8y=100.
Given the equation of circle 
and point at which the tangent meets the circle is (-6,8).
A tangent to a circle is basically a line at point P with coordinates is a straight line that touches the circle at P. The tangent is perpendicular to the radius which joins the centre of circle to the point P.
Linear equation looks like y=mx+c.
Tangent to a circle of equation
at (z,t) is:
xz+ty=
.
We have to just put the values in the formula above to get the equation of tangent to the circle
at (-6,8).
It will be as under:
x(-6)+y(8)=100
-6x+8y=100
Hence the equation of tangent to the circle at the point (-6,8) is -6x+8y=100.
Learn more about tangent of circle at brainly.com/question/17040970
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*see attachment for the figure described
Answer:
5 units
Step-by-step explanation:
==>Given the figure attached below, let where FH and EG intercepted be K.
Since FH are midpoints of parallel lines, KE = KG = x.
Given that the area of the kite EFGH = 35 square units, and we know the length of one of the diagonals = HF = KF + KH = 2 + 5 = 7, we can solve for x using the formula for the area of a kite.
Area of kite = ½ × d1 × d2
Where d1 = KH = 7
d2 = EG = KE + KG = x + x = 2x
Area of kite EFGH = 35
THUS:
35 = ½ × 7 × 2x
35 = 1 × 7 × x
35 = 7x
Divide both sides by 7
35/7 = x
x = 5