==>Given the figure attached below, let where FH and EG intercepted be K.
Since FH are midpoints of parallel lines, KE = KG = x.
Given that the area of the kite EFGH = 35 square units, and we know the length of one of the diagonals = HF = KF + KH = 2 + 5 = 7, we can solve for x using the formula for the area of a kite.
An equivalent fraction for 1/2 would be 2/4. This is because you can simplify 2/4 by dividing it by 2. The final answer would be 1/2. An equivalent fraction for 4/5 would be 8/10. It's basically the same thing. Divide them both by 2 and you'll get 4/5 since 8 divided by 2 is 4, and 10 divided by 2 is 5.