Observe the given data distribution table carefully.
The 5th class interval is given as,
The upper limit (UL) and lower limit (LL) of this interval are,
Thus, the upper-class limit of this 5th class is 17.4.
Answer:
Step-by-step explanation:
can u be more specific on what your asking for please
First represent your 3 consecutive integers as follows.
X ⇒ <em>first integer</em>
X + 1 ⇒ <em>second integer</em>
X + 2 ⇒ <em>third integer</em>
<em />
Since their sum is 84, our equation reads x + (x + 1) + (x + 2) = 84.
Simplifying on the left side we get 3x + 3 = 84.
Now subtract 3 from both sides to get 3x = 81.
Dividing both sides by 3, we find that <em>x = 27</em>.
Finally, make sure you list all your answers.
If <em>x </em>is 27 then <em>x </em>+ 1 is 28 and <em>x </em>+ 2 is 29.
Answer:
25
Step-by-step explanation:
I believe
-3^2 + -4^2
9+16=25
