Answer is 49
Formula is b^2-4(ac)
3^2-4(2*-5) while a=2, b=3, c=-5
9-4(2*-5)
9-4(-10)
9+40
49
Hope this helps!
The sum of the numbers should total to 1. Let us say that
x is the missing number, therefore:
x + ¼ + ¼ + 1/5 = 1
x = 1 – ¼ - ¼ - 1/5
The numbers should have similar denominator:
x = 20/20 – 5/20 – 5/20 – 4/20
x = 6/20
<span>x = 3/10</span>
It’s a question because there is not value of time.
