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barxatty [35]
3 years ago
13

Solve each equation. Show your work 13a=-5 12−b=12.5 -0.1=-10c

Mathematics
1 answer:
amid [387]3 years ago
5 0
1) 13a=-5
Make a the subject of the formula by dividing both sides by 13(the coefficient of a)
13a/13=-5/13
Therefore a= -0.385

The second one). 12-b= 12.5
You take the 12 to the other side making b subject of the formula (-b in this case)
-b= 12.5-12
-b= 0.5
(You cannot leave b with a negative sign so you will divide both sides by -1 to cancel out the negative sign)

-b/-1= 0.5/-1
Therefore b=-0.5

The third one). -0.1= -10c
You will divide both sides by the coefficient of c(number next to c) which is -10
-0.1/-10= -10c/-10

Hence, c= 0.01
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OlgaM077 [116]

Answer:

see below

Step-by-step explanation:

\frac{x-1}{x^2-3x+2}+ \frac{x-2}{x^2-5x+6} +\frac{x-5}{x^2-8x+15}

we need to simplify that

x^2-3x+2=(x-1)(x-2)\\\\x^2-5x+6=(x-2)(x-3)\\\\x^2-8x+15=(x-3)(x-5)

so we can continue

\frac{x-1}{(x-1)(x-2)}=\frac{1}{x-2}\\\\\frac{x-2}{(x-2)(x-3)} =\frac{1}{x-3}\\\\\frac{x-5}{(x-3)(x-5)} =\frac{1}{x-3}

and we can put all together

\frac{1}{x-2}+ \frac{1}{x-3}+ \frac{1}{x-3}\\\\\frac{1}{x-2} +\frac{2}{x-3}\\\\\frac{x-3}{(x-3)(x-2)}+ \frac{2(x-2)}{(x-2)(x-3)} \\\\\frac{x-3+2x-4}{(x-3)(x-2)}\\\\\frac{3x-7}{x^2-5x+6}

3 0
3 years ago
How does it factor out as that?
eimsori [14]
To factor out you have to think what multiples to AC and adds to B.

Ax^2+Bx+C

So... for this problem AxC=1x-24 or -24

B is -2.

So what two numbers multiply to -24: -3x8, -8x3, -4x6, -6x4, -2x12, -12x2.

Out of these, which adds to -2: -6+4=-2.

So the factors are (d-6)(d+4)

OR the longer way, which you really only use if A is not equal to 1.

Use the terms above and then rewrite the equation with two middle terms: d^2+4d-6d-24

Group the terms by using addition: (d^2+4d)+(6d-24)

Find what they have in common and factor it out. For the first, it's d. They both have d. So: d(d+4)
To check this, distribute the d. It should equal the first set lf parenthesis.

For the second, they have a number in common. 6 is a multiple of 24 so you can take that out: -6(d+4)

If the terms inside the parenthesis are the same, that's good. It means we can pair the insides and the outsides together to form the factors.

The two terms outside the parenthesis: d, -6 group together and become (d-6)

The inside terms stay the same: (d+4)

(d-6)(d+4)

Again, this is the longer way and no necessary for a problem like this. But if it was 2d^2, then this would be perfecf.




6 0
3 years ago
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