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barxatty [35]
3 years ago
13

Solve each equation. Show your work 13a=-5 12−b=12.5 -0.1=-10c

Mathematics
1 answer:
amid [387]3 years ago
5 0
1) 13a=-5
Make a the subject of the formula by dividing both sides by 13(the coefficient of a)
13a/13=-5/13
Therefore a= -0.385

The second one). 12-b= 12.5
You take the 12 to the other side making b subject of the formula (-b in this case)
-b= 12.5-12
-b= 0.5
(You cannot leave b with a negative sign so you will divide both sides by -1 to cancel out the negative sign)

-b/-1= 0.5/-1
Therefore b=-0.5

The third one). -0.1= -10c
You will divide both sides by the coefficient of c(number next to c) which is -10
-0.1/-10= -10c/-10

Hence, c= 0.01
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Step-by-step explanation:

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The sum of the nth term of a arithmetic sequence is given by;

S_n =\frac{n}{2}(2a+(n-1)d), where n is the number of terms, a is the first term and d is the common difference.

We also know the nth tern sequence formula which is given by ;

a_n = a+(n-1)d                             ......[2]

First find a.

it is given that a_{12} = 2.4

Put n =12 and d=3.4 in equation [2] we have;

a_{12} = a+(12-1)(3.4)

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Now, to calculate S_{22}

we use equation [1];

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S_{22} = \frac{22}{2}(2(-35)+(22-1)(3.4))

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S_{22} = (11)(1.4)

Simplify:

S_{22} = 15.4

Therefore, the sum of sequence of 22nd term i.e, S_{22} = 15.4

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