Given that the number of drivers who travel between a particular origin and destination during a designated time period has a Poisson distribution with parameter μ = 20 (suggested in the article "Dynamic Ride Sharing: Theory and Practice"†).

a) $P(X\leq 15) = 0.1565=0.157$

b) $P(X>26) =1-F(26)\\= 1-0.9221\\=0.0779=0.078$

c) $P(15\leq x\leq 26)\\=F(26)-F(14)\\=0.9221-0.1049\\=0.8172=0.817$

d) 2 std dev = 2(20) =40

Hence 2 std deviation means

20-40, 20+40

i.e. (0,60)

$P(0$

5 0

3 years ago

How would you draw this using a diagram?

ki77a [65]

Where is the diagram?

7 0

2 years ago

Area of 23ft^2 what is the length of a square

pentagon [3]

Step-by-step explanation:

Area=23ft²

Side=√23ft²

Side=4.8ft

4 0

2 years ago

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