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erik [133]
3 years ago
9

Divide 32x^4 - 12x^2 + 7x by 2x

Mathematics
2 answers:
kifflom [539]3 years ago
8 0

Answer:

16x^3 - 6x  + 7/2

Step-by-step explanation:

32x^4 - 12x^2 + 7x by 2x

32x^4/2x =  16x^3

- 12x^2/2x = - 6x

 7x /2x = 7/2

So

32x^4 - 12x^2 + 7x by 2x =

16x^3 - 6x  + 7/2

nikitadnepr [17]3 years ago
4 0

For this case we must divide the following expressions:

32x ^ 4-12x ^ 2 + 7x between 2x:

\frac {32x ^ 4-12x ^ 2 + 7x} {2x} =

Separating terms:

\frac {32x ^ 4} {2x} - \frac {12x ^ 2} {2x} + \frac {7x} {2x} =

We simplify:

16x ^ 3-6x + \frac {7} {2}

Thus, \frac {32x ^ 4-12x ^ 2 + 7x} {2x} = 16x ^ 3-6x + \frac {7} {2}

Answer:

16x ^ 3-6x + \frac {7} {2}

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