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docker41 [41]
3 years ago
11

How do you this 3 (g-3)=6

Mathematics
2 answers:
Elenna [48]3 years ago
4 0
3(g-3)=6
3g-9=6
3g=15
g=5
that's the answer

KIM [24]3 years ago
4 0
Divide 3=
g-3=6/3
Simplify 6/3 to 2
g-3=2
Add 3
g=5
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Write the equation of the line that passes through (-1, 3) and is parallel to the line y = -x + 1.
ra1l [238]

Answer:

Step-by-step explanation:

y = -x + 1......same as y = -1x + 1.....in y = mx + b form, ur slope is in the m position....so the slope of this line is -1.

a parallel line will have the same slope.

(-1,3)...x = -1 and y = 3

slope(m) = -1

y = mx + b.....we have x,y, and m....now we need to find y int (b)

3 = -1(-1) + b

3 = 1 + b

3 - 1 = b

2 = b

so ur parallel equation is : y = -1x + 2...or just y = -x + 2

7 0
3 years ago
Write each fraction as a decimal. Then identify each decimal as terminating or repeating.
cluponka [151]
1/6 = 0.16
1/8 = 0.125
1/11 = 0.09
2/9 = 0.22
4/5 = 0.8
5/9 = 0.56
1/2 = 0.5
7/9 = 0.78
5 0
3 years ago
3 of 5<br> Simplify as far as possible without a calculator.<br> 33(272+273)
inn [45]

Answer:

17,985

Step-by-step explanation:

33(545)= 17,985

3 0
3 years ago
Read 2 more answers
What is the distance between the points (5,2) and (-9,-2)?​
Tanya [424]
Between 5 and -9 it’s 14 units and between 2 and -2 it’s 4
6 0
3 years ago
IQ scores are measured with a test designed so that the mean is 116 and the standard deviation is 16. Consider the group of IQ s
butalik [34]

Answer:

So the z-scores that separate the unusual IQ scores from those that are​ usual are Z = -2 and Z = 2.

The IQ scores that separate the unusual IQ scores from those that are​ usual are 84 and 148.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 116, \sigma = 16

What are the z scores that separate the unusual IQ scores from those that are​ usual?

If Z<-2 or Z > 2, the IQ score is unusual.

So the z-scores that separate the unusual IQ scores from those that are​ usual are Z = -2 and Z = 2.

What are the IQ scores that separate the unusual IQ scores from those that are​ usual?

Those IQ scores are X when Z = -2 and X when Z = 2. So

Z = -2

Z = \frac{X - \mu}{\sigma}

-2 = \frac{X - 116}{16}

X - 116 = -2*16

X = 84

Z = 2

Z = \frac{X - \mu}{\sigma}

2 = \frac{X - 116}{16}

X - 116 = 2*16

X = 148

The IQ scores that separate the unusual IQ scores from those that are​ usual are 84 and 148.

8 0
3 years ago
Read 2 more answers
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