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Gnoma [55]
3 years ago
6

Simplify 7xy^2z^3- 4xy^2z^3+2x^2yz^2-3xy^2z^3

Mathematics
1 answer:
aksik [14]3 years ago
3 0

Answer:

(Hope this helps can I pls have brainlist (crown)☺️)

Step-by-step explanation:

In pic

(Credits:Symbolab)

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For functions f(x)=x^2−5x−24 and g(x)=x+3, find a. (fg)(x) b. (fg)(−3)
koban [17]
Something that I’m not sure how to answer f(x) 16362
8 0
3 years ago
Select all of the words that represent the answer to a quadratic equation (there are 4 answers).
Inessa [10]

Answer:

see explanation

Step-by-step explanation:

The words used to represent answers to a quadratic equation are

• x- intercepts

• solutions

• roots

• zeros

5 0
2 years ago
Need help!!!<br> What is the real part of z?<br><br> What is the imaginary part of z?
Andrej [43]

Step-by-step explanation:

z_z=wdyxdhxfbxtbxfhcthcdybxfjcdtcxtbxdgcdtgxrbxdh cg cgbcyv

7 0
3 years ago
The bending of a bean varies directly as its mas. A beam is bent 20mm by a mass 0f 40kg. how much will the beam bend with a mass
Naddik [55]

Answer:

The beam will bend by 50 mm with a mass of 100kg?

Step-by-step explanation:

The first step in solving the problem of direct variation is setting up the relation mathematically.

We can do this as follows:

The bending of the beam varies directly as its mass.

20  \alpha  40kg

\alpha here is the symbol representing direct variation. To remove this and replace it with an equality sign, we have to introduce a constant of proportionality, k

20 = k \times 40

k = 20 /40 = 0.5

We can now use this to find the distance the beam will bend with a mass of 100kg?

This will be

Bending = 0.5 \times 100 =50mm

There fore, the beam will bend by 50 mm with a mass of 100kg?

6 0
3 years ago
Read 2 more answers
How much material is needed to construct a triangular tent that is 6 feet wide 4 feet tall and 8 feet long with side measurement
jonny [76]

Answer: 152ft^2

The amount of material needed to construct the tent is 152ft^2

Step-by-step explanation:

The amount of material needed to construct a triangular tent= the surface area of the triangular tent.

S.A = area of the 2 side rectangles + area of the 2 side triangles + area of the base.

S.A = Ab + At + Ar ....1

Area of the base Ab= Length × width = 8×6 = 48ft^2

Area of the two triangles At = 2 × 0.5 × width × height

At = width × height = 6×4 = 24ft^2

Area of the two rectangles Ar = 2 × side measurement × length

Side measurement is given as 5ft.

or it can be calculated using;

Side length can be calculated using Pythagoras theorem.

Examining the figure attached, we can see that;

Side breadth b = √(h^2 + (w/2)^2)

b = √(4^2 + (6/2)^2) = √(16+9) = √25

b = 5ft

Ar = 2×5×8 = 80ft^2

From eqn1, S.A can be solved as;

S.A = 48 + 24 + 80

S.A = 152ft^2

7 0
3 years ago
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