Answer:
17 ± sqrt(337)
-----------------------
2
Step-by-step explanation:
Let a = shorter leg
b= longer leg = a+7
c = hypotenuse = 2a-5
We can use the Pythagorean theorem
a^2+b^2 = c^2
a^2 + (a+7)^2 = (2a-5)^2
(a+7)^2 = a^2 +7a +7a+49 = a^2 +14a +49
(2a-5)^2 = 2a*2a -10a -10a +25 = 4a^2 -20a +25
Substituting these into the equation
a^2 + (a^2 +14a +49) = (4a^2 -20a +25)
Combine like terms
2a^2 +14a +49 = 4a^2 -20a +25
Subtracting 2a^2 from each side
2a^2 -2a^2 +14a +49 = 4a^2-2a^2 -20a +25
+14a +49 = 2a^2 -20a +25
Subtract 14a from each side
-14a+14a +49 = 2a^2 -20a -14a+25
+49 = 2a^2 -34a +25
Subtract 49 from each side
49-49 = 2a^2 -34a +25-49
0 = 2a^2 -34a -24
Divide each side by 2
0/2 = 2/2a^2 -34/2a -24/2
0 = a^2 -17a -12
Using the quadratic formula
a=1 b= -17 c = -12
17 ±sqrt( (-17)^2 - 4(1)(-12))
----------------------------------
2(1)
17 ± sqrt(337)
-----------------------
2
Answer:
Step-by-step explanation:
answer is 
The fraction of the original mass that was lost in the second month is 1/12.
<h3>What is the fraction?</h3>
A fraction is a non-integer that is made up of numerators and denominators. An example of a fraction is 1/10.
Weight lost in the first month = 1/6 x 120 = 20kg
Weight lost in the second month = 1/10 x (120 - 20)
= 1/10 x 100 = 10kg
Fraction of the original mass that was lost in the second month : weight lost in the second month / total mass
10 kg / 120 = 1/12
To learn more about multiplication of fractions, please check: brainly.com/question/1114498
#SPJ1
Answer:
3
Step-by-step explanation:
In this case, Luis has 6 quarters, and 3 dimes. 6 - 3 = 3, and it works out to the following:
6 • 0.25 = 1.50
3 • 0.10 = 0.30
1.50 + 0.30 = 1.80
Answer:
This above options makes the expression true.
- The negatives above can be distributed up as well, which happened in A.
- In E, when the negatives inside the bracket cancels out, the negative outside the brackets multiplies and makes the expression true.
- In B the expression turns positive, thus false same happens with C and D
