Answer/Explanation:
Density-dependent limiting factors are non living and biotic factors that affect the size and growth of a population based on the population density, while density-independent limiting factors are those factors that do not depend on the density of a population before they can have an effect on the growth and size of the population.
Examples of density-dependent limiting factors are predation, disease, Parasitism, competition. These rely on the density of a population in order to affect the growth and size of a population.
On the other hand, examples of density-independent limiting factors are pollution, flood, temperature.
Answer:
The genotype of both parents is RrYy.
The possible types of gametes would be RY, Ry, rY, and ry.
The cross would produce offspring that can have one out of four types of phenotypes:
- Round and yellow seeds (1 RRYY+ 2 RrYY +2 RRYy + 4 RrYy) = 9/16
- Wrinkled and yellow seeds (3 rrYy) = 3/16
- Round and green seeds (1 RRyy + 2 Rryy) = 3/16
- Wrinkled and green seeds (rryy) = 1/16
Thus, one out of 16 offspring would have wrinkled and green seeds.
Answer:
The correct answer will be option-D.
Explanation:
In the given question doctor used the scientific method to understand and explain the natural phenomenon.
The scientific method involves various steps like making an observation followed by background research, predicting a hypothesis and performing tests to test the hypothesis. These steps have been performed by the doctor.
After these steps the doctor will analyse the result and reach to the conclusion. This would be followed by publishing the results in a scientific journal where it would be reviewed by the fellow scientists.
Therefore, the next step will be publishing the result and thus option-D is the correct answer.
Answer:
Explanation:
Mendel's law of independent assortment state that two different genes assort independently in gamete formation.
To reach this conclusion, one has to do a dihybrid cross. This means that two genes responsible for different traits need to be analyzed at the same time.
1) Starting with a <u>parental generation of a cross between two pure lines</u> (homozygous for both genes) <u>with different traits</u>, a plant with yellow and round seeds (YYRR) and another with green and wrinkled seeds (yyrr). <u>The F1 will be phenotypically homogeneous (</u>yellow and round)<u>, and genotypically heterozygous (</u><u>YyRr</u><u>)</u>.
2) If the individuals from the F1 are crossed with one another, we have to do a Punnett Square to determine the phenotypic ratio of the F2.
- If the genes assort independently, the F1 individuals will produce their different gametes with the same probability. Each possible gamete will appear in a 1/4 proportion: YR, Yr, yR, yr.
- The 9:3:3:1 ratio is a result of analyzing the possible phenotypes that result from the dihybrid cross.
See the attached image for an illustration of the crosses in each generation and the Punnett Square.
the answer is B) Cats favor the use of one paw over the other
Joyce figures that is humans have a dominant hand, cats must have a dominant paw too. The point of the experiment was to see which paw the cats used more, and that would be considered their dominant paw.