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sashaice [31]
3 years ago
11

Gregorio took two tests. Find his z-score for each test. (Remember: The number of standard deviations between a score and the me

an score is indicated by a z-score.) On which did he score better compared with others in his class?

Mathematics
1 answer:
never [62]3 years ago
5 0
I found the missing parts of this question.
Test A 
<span>Gregorio’s score </span><span>62 </span>
<span>Mean score </span><span>80 </span>
<span>Standard deviation </span><span>6 </span>

<span>Test B </span>
<span>Gregorio's score </span><span>70 </span>
<span>Mean score </span><span>90 </span>
<span>Standard deviation </span><span>10 </span>


<span>a. </span><span>Test A: 3; Test B: 2; Test A </span>
<span>c. </span><span>Test A: –2; Test B: –3; Test A </span>
<span>b. </span><span>Test A: –3; Test B: –2; Test B </span>
<span>d. </span><span>Test A: –3; Test B: –2; Test A
</span>

Refer to the attachment for the formula of z score:

test A: z = (62-80)/6  = -18/6 = -3
test B: z = (70-90)/10 = -20/10 = -2

B. <span>Test A: –3; Test B: –2; Test B </span>

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Which expression is represented on the number line? ​
frozen [14]

Answer:

b

Step-by-step explanation:

because it is -2 four times and if you do -2 ×4 you get -8. hope thid helped

5 0
2 years ago
Simplify (−4k4+14+3k2)+(−3k4−14k2−8). Write answer in standard form.
marissa [1.9K]

Answer:

−7k^4−11k^2+6

Step-by-step explanation:

−4k^4+14+3k^2−3k^4−14k^2−8

(−4k^4+−3k^4)+(3k^2+−14k^2)+(14+−8)

−7k^4−11k^2+6

...

8 0
2 years ago
What is 10*10? Please help! :) ​
Zigmanuir [339]

Answer:

100

Step-by-step explanation:

It will help in the future to memorize your time tables

10*10 is basically 10 plus 10, 10 times but in a easier form

10+10+10+10+10+10+10+10+10+10=100

10+10=20

20+10=30

30+10=40

40+10=50

50+10=60

60+10=70

70+10=80

80+10=90

90+10=100

5 0
3 years ago
What set of reflections would carry trapezoid ABCD onto itself? (1 point) Trapezoid ABCD is shown. A is at negative 5, 1. B is a
amid [387]

Answer:

y=x, x axis,  y=x, y axis

Step-by-step explanation:

If a point A(x, y) is reflected along the y = x line, the new coordinates would be A'(y, x)

If a point A(x, y) is reflected across the x axis, the new coordinates would be A'(x, -y)

If a point A(x, y) is reflected along the y axis, the new coordinates would be A'(-x, y)

Firstly reflect Trapezoid ABCD along the y = x line to give:

A (-5, 1) ⇒ A'(1, -5). B (-4, 3) ⇒ B'(3, -4). C (-2, 3) ⇒C'(3, -2). D (-1, 1) ⇒ D'(1, -1)

Secondly reflect along the x axis to give:

A'(1, -5)⇒ A"(1,5). B'(3, -4)⇒ B"(3,4), C'(3, -2)⇒C"(3, 2), D'(1, -1) ⇒ D"(1, 1)

Thirdly reflect along the y = x line to give:

A"(1,5) ⇒ A"'(5, 1). B"(3,4) ⇒ B"'(4, 3). C"(3, 2) ⇒ C"'(2, 3). D"(1, 1) ⇒ D"'(1, 1)

Lastly reflect along the y axis to give:

A"'(5, 1) ⇒ A""(-5, 1), B"'(4, 3) ⇒ B""(-4, 3), C"'(2, 3) ⇒ C""(-2, 3), D"'(1, 1) ⇒ D""(-1.1)

6 0
3 years ago
Product of 4h × 5m is what
scoundrel [369]

20hm

That simple!. Good Luck.

4 0
3 years ago
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