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sashaice [31]
3 years ago
11

Gregorio took two tests. Find his z-score for each test. (Remember: The number of standard deviations between a score and the me

an score is indicated by a z-score.) On which did he score better compared with others in his class?

Mathematics
1 answer:
never [62]3 years ago
5 0
I found the missing parts of this question.
Test A 
<span>Gregorio’s score </span><span>62 </span>
<span>Mean score </span><span>80 </span>
<span>Standard deviation </span><span>6 </span>

<span>Test B </span>
<span>Gregorio's score </span><span>70 </span>
<span>Mean score </span><span>90 </span>
<span>Standard deviation </span><span>10 </span>


<span>a. </span><span>Test A: 3; Test B: 2; Test A </span>
<span>c. </span><span>Test A: –2; Test B: –3; Test A </span>
<span>b. </span><span>Test A: –3; Test B: –2; Test B </span>
<span>d. </span><span>Test A: –3; Test B: –2; Test A
</span>

Refer to the attachment for the formula of z score:

test A: z = (62-80)/6  = -18/6 = -3
test B: z = (70-90)/10 = -20/10 = -2

B. <span>Test A: –3; Test B: –2; Test B </span>

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<u>Answer-</u>

<em>The lines are two </em><em>coinciding lines</em><em> or the </em><em>same lines</em><em>.</em>

<u>Solution-</u>

The given line equations are

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\Rightarrow y+1=\dfrac{1}{5}(x+5)\\\\\Rightarrow 5y+5=x+5\\\\\Rightarrow 5y=x\\\\\Rightarrow x-5y=0

As we know two line equations A_1x+B_1y+C_1=0 and A_2x+B_2y+C_2=0 will be,

  1. Parallel if, \dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}
  2. Coincide if, \dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}=\dfrac{C_1}{C_2}
  3. Intersect if, \dfrac{A_1}{A_2}\neq \dfrac{B_1}{B_2}

As here,

\Rightarrow \dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}=\dfrac{C_1}{C_2}

\Rightarrow \dfrac{1}{1}=\dfrac{-5}{-5}

(C₁ and C₂ aren't considered as they are 0)

Therefore, the lines are two coinciding lines or the same lines.

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3 years ago
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5. The Riverside Geyser in Yellowstone National Park erupts
Anastasy [175]

Answer:

Step-by-step explanation:

<h3>A.</h3>

The equation for the model of the geyser is found by substituting the given upward velocity into the vertical motion model. The problem statement tells us v=69. We assume the height is measured from ground level, so c=0. Putting these values into the model gives ...

  h(t) = -16t² +69t

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<h3>B.</h3>

The maximum height is at a time that is halfway between the zeros of the function.

  h(t) = -16t(t -4.3125) . . . . . has zeros at t=0 and t=4.3125

The maximum height will occur at t=4.3125/2 = 2.15625 seconds. The height at that time is ...

  h(t) = -16(2.15625)(2.15625 -4.3125) = 16(2.15625²) ≈ 74.39 . . . feet

The maximum height of the geyser is about 74.4 feet.

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2 years ago
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This exercise involves the formula for the area of a circular sector. The area of a circle is 700 m2. Find the area of a sector
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Answer:

334.4 m²

Step-by-step explanation:

The formula for the area of a sector is given as:

1/2 × r² × θ

Where θ = Central angle

Area of a Circle = 700 m²

The formula for the area of a circle = πr²

r = Radius of a circle

r² = Area / π

r = √Area / π

r = √700/π

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Approximately, r = 14.93 m

Therefore, the area of the sector

= 1/2 × r² × θ

= 1/2 × 14.93² × 3 rad

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Approximately, Area of the sector = 334.4 m²

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