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2 years ago

Using the recurrence relation s(1) = 2 and s(2)=3, s(k) =s(k-1)+2s(k-2)+6, find the fourth term

1 answer:

6 0

Recurrence functions are used to preedict the subsequent value in a sequence. The fourth term of the sequence based on the recurrence relation is 25

<h3>How to find the recurrence relation of a function?</h3>

Given the recurrence relations according to the question

s(1) = 2 and

s(2)=3

s(k) =s(k-1)+2s(k-2)+6

If s(1) = 2, hence;

s(3) =s(3-1)+2s(3-2)+6

s(3) = s2 + 2s1 + 6
s(3) = 3 + 2(2) + 6
s(3) = 13

Determine the fourth term:

s(4) =s(4-1)+2s(4-2)+6

s(4) = s3 + 2s2 + 6
s(4) = 13 + 2(3) + 6
s(4) = 25

Hence the fourth term of the sequence based on the recurrence relation is 25

Learn more on recurrence relation here: brainly.com/question/10636530

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