Answer: y=2
Step-by-step explanation:
2x+3y=14 - 2x-y=6 = 4y=8
y=2
If you need x, just insert y into the equation and work out x from there
2x-2=6
2x=8
x=4
Answer:
hope this helped you
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Answer:
6.31 mi
Step-by-step explanation:
The diagram below explains the solution better.
From the diagram,
C = starting point of the race.
A = end of the first part of the race.
B = end of the race.
Using Cosine rule, we can find the straight-line distance between the starting point and the end of the race.
Cosine rule states that:
![a^2 = b^2 + c^2 - 2bc[cos(A)]](https://tex.z-dn.net/?f=a%5E2%20%3D%20b%5E2%20%2B%20c%5E2%20-%202bc%5Bcos%28A%29%5D)
where A = angle A = <A
Given that
b = 5.2 miles
c = 2.0 miles
<A = 115° (from the diagram)
Hence,
![a^2 = 5.2^2 + 2.0^2 - 2*5.2*2.0[cos(115)]\\\\a^2 = 27.04 + 4 - 20.8[cos(115)]\\\\a^2 = 31.04 + 8.79\\\\a^2 = 39.83\\\\a = \sqrt{39.83}\\ \\a = 6.31 mi](https://tex.z-dn.net/?f=a%5E2%20%3D%205.2%5E2%20%2B%202.0%5E2%20-%202%2A5.2%2A2.0%5Bcos%28115%29%5D%5C%5C%5C%5Ca%5E2%20%3D%2027.04%20%2B%204%20-%2020.8%5Bcos%28115%29%5D%5C%5C%5C%5Ca%5E2%20%3D%2031.04%20%2B%208.79%5C%5C%5C%5Ca%5E2%20%3D%2039.83%5C%5C%5C%5Ca%20%3D%20%5Csqrt%7B39.83%7D%5C%5C%20%5C%5Ca%20%3D%206.31%20mi)
The straight-line distance between the starting point and the end of the race is 6.31 mi
Rhombus, Parallelogram, Kite, Rectangle, Square, Trapezoid, Isosceles Trapezoid
1 foot = 12 inches
Height of Jacob = 5 feet 6 inches = 5 *12 + 6 = 66 inches
Jacob's <span>shadow = 3 feet = 36 inches
</span>giraffe's shadow = <span>5 feet 9 inches = 5 * 12 + 9 = 69 inches
</span><span>by
the ratio and proportion
∴ </span>Height of Jacob/Jacob's shadow = Height of giraffe/giraffe's shadow
∴ 66/36 = Height of giraffe/69
∴ Height of giraffe = 69 * 66/36 = 126.5 inches = 10 feet 6.5 inches