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yawa3891 [41]
3 years ago
15

Jeff was counting the squirrels and birds in the park. He counted 16 heads and 44 legs. How many birds did Jeff count?

Mathematics
1 answer:
hodyreva [135]3 years ago
4 0
So 1 head per squirel and 1 head per bird
4 legs per squirel and 2 legs per bird
s=number of squirels
b=birds
the equatinos should be
1b+1s=number of heads=16
and
2b+4s=number of legs=44
(note 2b=2 times b)
so we aolve

b+s=16 and 2b+4s=44
simplify the second equaiton by divideinb by 2
2b+4s=44
divide 2
b+2s=22

b+s=16
and
b+2s=22
we can actually add the two equations together with the first one made negative
-b-s=-16
<u>b+2s=22+</u>
0b+1s=6
s=6
subsitute
b+s=16
b+6=16
subtract 6 from both sides
b=10


10 birds
answer is c

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I look at a random time of day at a digital clock that shows times from 1:00 through 12:59. if i ignore the colon, what is the p
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3 years ago
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Multiply the polynomials show steps
Karo-lina-s [1.5K]

Answer:

3a^{4} + 11a³ - 7a² + 18a - 18

Step-by-step explanation:

<u>When multiplying with two brackets, you need to multiply the three terms, (a²), (4a) and (-6) from the first bracket to all the terms in the second brackets, (3a²), (-a) and (3) individually. I have put each multiplied term in a bracket so it is easier.</u>

(a² + 4a - 6) × (3a² - a + 3) =

(a² × <em>3a²</em>) + {a² × <em>(-a)</em>} + (a² × <em>3</em>) + (4a × <em>3a²</em>) + {4a × <em>(-a)</em>} + (4a × <em>3</em>) + {(-6) × <em>a²</em>) + {(-6) × <em>(-a)</em>} + {(-6) × <em>3</em>}

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<u>We can open the brackets now. One plus and one minus makes a minus. </u>

3a^{4} + (-a³) + 3a² + 12a³ + (-4a²) + 12a + (-6a²) + 6a + (-18) =

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A. Use composition to prove whether or not the functions are inverses of each other. B. Express the domain of the compositions u
Kryger [21]

Given: f(x) = \frac{1}{x-2}

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f(\frac{2x+1}{x} )=1

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g(f(x))= g(\frac{1}{x-2} )

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g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}

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