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yawa3891 [41]
3 years ago
15

Jeff was counting the squirrels and birds in the park. He counted 16 heads and 44 legs. How many birds did Jeff count?

Mathematics
1 answer:
hodyreva [135]3 years ago
4 0
So 1 head per squirel and 1 head per bird
4 legs per squirel and 2 legs per bird
s=number of squirels
b=birds
the equatinos should be
1b+1s=number of heads=16
and
2b+4s=number of legs=44
(note 2b=2 times b)
so we aolve

b+s=16 and 2b+4s=44
simplify the second equaiton by divideinb by 2
2b+4s=44
divide 2
b+2s=22

b+s=16
and
b+2s=22
we can actually add the two equations together with the first one made negative
-b-s=-16
<u>b+2s=22+</u>
0b+1s=6
s=6
subsitute
b+s=16
b+6=16
subtract 6 from both sides
b=10


10 birds
answer is c

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Step-by-step explanation:

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Here adjacent side = 6

opposite side = d

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tan (45) = Opposite ÷ Adjacent

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opposite side = d

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therefore d = \frac{4}{3}

therefore opposite side = \frac{4}{3}

Hypotenuse ² = opposite side ² + adjacent side²

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