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yawa3891 [41]
2 years ago
15

Jeff was counting the squirrels and birds in the park. He counted 16 heads and 44 legs. How many birds did Jeff count?

Mathematics
1 answer:
hodyreva [135]2 years ago
4 0
So 1 head per squirel and 1 head per bird
4 legs per squirel and 2 legs per bird
s=number of squirels
b=birds
the equatinos should be
1b+1s=number of heads=16
and
2b+4s=number of legs=44
(note 2b=2 times b)
so we aolve

b+s=16 and 2b+4s=44
simplify the second equaiton by divideinb by 2
2b+4s=44
divide 2
b+2s=22

b+s=16
and
b+2s=22
we can actually add the two equations together with the first one made negative
-b-s=-16
<u>b+2s=22+</u>
0b+1s=6
s=6
subsitute
b+s=16
b+6=16
subtract 6 from both sides
b=10


10 birds
answer is c

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Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
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  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

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Step-by-step explanation:

<u>Step 1: Define</u>

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<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Add 8 on both sides:                    4x > 40
  2. Divide 4 on both sides:                x > 10

Here we see that any value <em>x</em> greater than 10 would work as a solution to the inequality.

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