Answer:
$2000 was invested at 5% and $5000 was invested at 8%.
Step-by-step explanation:
Assuming the interest is simple interest.
<u>Simple Interest Formula</u>
I = Prt
where:
- I = interest earned.
- P = principal invested.
- r = interest rate (in decimal form).
- t = time (in years).
Given:
- Total P = $7000
- P₁ = principal invested at 5%
- P₂ = principal invested at 8%
- Total interest = $500
- r₁ = 5% = 0.05
- r₂ = 8% = 0.08
- t = 1 year
Create two equations from the given information:


Rewrite Equation 1 to make P₁ the subject:

Substitute this into Equation 2 and solve for P₂:





Substitute the found value of P₂ into Equation 1 and solve for P₁:



$2000 was invested at 5% and $5000 was invested at 8%.
Learn more about simple interest here:
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12(t + 2) + 4 ≥ - 8
12t + 24 + 4 ≥ - 8
12t + 28 ≥ - 8
12t ≥ - 8 - 28
12t ≥ - 36
t ≥ - 36 ÷ 12
t ≥ - 3
Solution:
t ≥ -3
Answer:
98.28
Step-by-step explanation:
its kinda easy
Answer:
idk
Step-by-step explanation:
Answer:
This proves that f is continous at x=5.
Step-by-step explanation:
Taking f(x) = 3x-1 and
, we want to find a
such that 
At first, we will assume that this delta exists and we will try to figure out its value.
Suppose that
. Then
.
Then, if
, then
. So, in this case, if
we get that
. The maximum value of delta is
.
By definition, this procedure proves that
. Note that f(5)=14, so this proves that f is continous at x=5.