That would be Graph C
The solution is where the 2 graphs intersect At A and B.
x + y + 2 = 0 transforms to y = -x - 2 which has slope -1 and y-intercept of -2
as in Graph C.
I + 6 = r
4r = s
i + r + s = 126
4i + 24 = 4r
s= 4r
i = r-6
4i+24=i+6
-3i=18
i = 6
Solve the rest
Answer:
<h3>B. -84</h3>
Step-by-step explanation:
Taking the determinant of the matrices we will have;
= 4x(5y) - 2x(3y)
= 20xy - 6xy
= 14xy
Given x = -2 and y = 3
Determinant = 14(-2)(3)
Determinant = -28*3
Determinant = -84
So discriminant gives us 3 possibilites connected with result of the equation b^2-4ac. If it is bigger than zero, there are 2 solutions, if answer is exactly 0, then there is one answer and if the number is lower than 0, there are no solutions.
Discriminant of your quadratic equation is (-4)^2-4*1*5=16-20=-4, so there are no solutions.
