All categories

3 years ago

Match the two numbers with their least common multiple (LCM).

Mathematics

2 answers:

jarptica [38.1K]3 years ago

8 0

Answer:

Step-by-step explanation:

We have to find the LCM of the given numbers and match then with their options given.

LCM of 10 and 4

factors of 10 = 2 × 5

factors of 4 = 2 × 2

LCM = 2 × 5 × 2 = 20 Matches (C)

LCM of 10 and 6

factors of 10 = 2 × 5

factors of 6 = 2 × 3

LCM = 2 × 3 × 5 = 30 Matches (A)

LCM of 10 and 8

factors of 10 = 2 × 5

factors of 8 = 2 × 2 × 2

LCM = 2 × 5 × 2 × 2 = 40 Matches (B)

eduard3 years ago

7 0

LCM:
10: 0,10,20,30,40,50
4: 0,4,8,12,16,20
ANSWER IS 20

LCM:
10: see above numbers
6: 0,6,12,18,24,30
ANSWER IS 30

So, 10 and 8 would be 40

You might be interested in

Help i dont know what to do

oksano4ka [1.4K]

Answer:

Pretend the y-axis is a mirror

If the original shape is

P=4,-2

Z=5,-4

M=4,-4

The new image made by mirroring it will be

P’= -4,-2

Z’= -5,-4

M’= -4,-4

Step-by-step explanation:

Sorry if this doesn’t make sense, just graph P’, Z’, and M’ for a mirrored image

3 0

2 years ago

Fatima is shading this model to show 0.08x3 . shade the correct amount of boxes that will show the product

Karo-lina-s [1.5K]

Shade 0.08 3 times

In total that's 24 hundreths to shade

For more help, please upload a picture

Hope this helps!!

7 0

2 years ago

Of the 345 7th graders, 40% of them<br> are in band. How many 7 graders<br> are in band?

xz_007 [3.2K]

So first you find 10% which is 34.5
Then you multiply 10% by 4 to get 40% which is = 138

3 0

2 years ago

Read 2 more answers

a glass of jar contains 1 red, 3 green and 2 blue marbles. asingle marble is chosen at random from the jar and its color is reco

lubasha [3.4K]

hi,

first let's count the marbles : 1+3+2 = 6

so picking a red is 1/6

a green is : 3/6

a bleu is : 2/6

4 0

3 years ago

The perimeter of a rectangle is 42 inches, and its area is 110 square inches. find the length and width of the rectangle.

lorasvet [3.4K]

$p = 2w + 2l$ $p = 42$
$a = l * w$ $a = 108$

You want to make either the length or width variable (I chose the width variable to be by itself. It doesn't matter) by itself by:

Divide both sides by 2.
(p) ÷ 2 = (2w + 2l) ÷ 2
$2's$ $cancel$ $out$
$\frac{p}{2} = w + l$

Subtract both sides by either length or width depending on what variable you chose to make by itself (in this case I subtracted the length variable because I wanted the width variable by itself).
$\frac{p}{2} - l = w + l - l$
$l's$ $cancel$ $out$
p/2 - l = w

$a = l * w$

You replace w with the equation above p/2 - l = w
$a = l( \frac{p}{2} - l)$

Multiply out the L.
$a = \frac{p}{2}l - l^{2}$

Plug in all your numbers a = 110 and p = 42
$110 = \frac{42}{2}l - l^{2}$
$110 = 21l - l^{2$

Move everything to the left side so $l^{2}$ would be positive (makes the equation easier when $l^{2}$ is positive).
$l^{2} - 21l + 110 = 0$

Factor.
$(l -10)(l-11) = 0$

Make each parenthesis set equal to 0.
$l-11=0$ $l-10=0$

Add.
$l = 11$ $l = 10$

By doing this you solve for both the width and length so the answer is:
w = 11 L = 10

8 0

3 years ago