3 years ago

use the rules for multiplication by powers of 10 to calculate 20 × 100. a. 200 b. 20 c. 2,000 d. 20,000

Mathematics

2 answers:

Musya8 [376]3 years ago

6 0

The answer is c 2,000

Gnesinka [82]3 years ago

4 0

It is two thousand, so C. I use the multiplication where you put one number above the other.

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I need help with this please. :)

jek_recluse [69]

9514 1404 393

Answer:

2x
2
128x +640

Step-by-step explanation:

$\displaystyle\frac{8x^2-4x}{4x-2}=\frac{4x(2x-1)}{2(2x-1)}=\boxed{2x}$

$\displaystyle\frac{8x-4}{x+3}-\frac{12x-20}{2x+6}=\frac{8x-4}{x+3}-\frac{4(3x-5)}{2(x+3)}=\frac{8x-4-2(3x-5)}{x+3}\\\\=\frac{8x-4-6x+10}{x+3}=\frac{2x+6}{x+3}=\frac{2(x+3)}{x+3}=\boxed{2}$

$\displaystyle\frac{(2x+10)^7}{(x+5)^6}=\frac{(2(x+5))^7}{(x+5)^6}=2^7(x+5)^{7-6}=128(x+5)\\\\=\boxed{128x+640}$

5 0

3 years ago

55% of 70 round to the nearest tenth

Verizon [17]

70 * 55/100=38.5

Enjoy

3 0

3 years ago

Read 2 more answers

Find the zeros (roots) of the following equations. f(x) = 2x5 - 9x4 + 12x3 - 12x2 + 10x - 3 = 0

Talja [164]

Hi,
$f(1)=2*1^5-9*1^4+12*1^3-12*1^2+10*1-3\\
=2-9+12-12+10-3\\
=0\\

f(x)=(x-1)(2x^4-7x^3+5x^2-7x+3)\\


g(x)=2x^4-7x^3+5x^2-7x+3\\

g(3)=2*3^4-7*3^3+5*3^2-7*3+3\\
=162-189+45-21+3\\
=0\\

g(x)=(x-3)(2x^3-x^2+2x-1)\\

h(x)=2x^3-x^2+2x-1\\

h( \dfrac{1}{2} )=2* \dfrac{1}{8} - \dfrac{1} {4}+1-1\\
=0\\

h(x)=(2x-1)(x^2+1)\\


f(x)=(x-1)(x-3)(2x-1)(x+i)(x-i)\\


$
Roots are 1,3,0.5,i,-i.

8 0

3 years ago

john owns a truck. he rents out the truck with himself as a driver for $75 per hour. last month john earned $6375 how many of ho

Airida [17]

It would be 85 hours because 6375÷75=85

4 0

3 years ago

Don’t mind the work but can someone please help fast I’m stuck!! I also need to show work

balu736 [363]

Answer:

The answer for this problem is at the bottom of picture.

4 0

3 years ago