Answer:
7.5 +9.63.
7.5+9.63. + N
17.13N
is the answer
Step-by-step explanation:
Answer:
2
Step-by-step explanation:
Using the rule of logarithms
• 
x = n ⇔ x = 
let 
64 = n, then
64 = 
note that 64 = 8², thus
8² = ⇒ n = 2
The 95% confidence interval for the true percent of car owners in this city who received a speeding ticket this year is 44.63% to 49.37%
The formula for calculating the confidence interval is expressed as:
CI = p±z√p(1-p)/n
Given the following parameters
n = 1700
p = 799/1700
p = 0.47
z-score at 95% interval = 1.96
Substitute the given values
CI = 0.47 ±1.96√0.47(1-0.47)/1700
CI =0.47 ±1.96(0.0121)
CI = 0.47±0.0237
CI = 0.47+0.0237, 0.47-0.0237
CI = (0.4463, 0.4937)
Hence the 95% confidence interval for the true percent of car owners in this city who received a speeding ticket this year is 44.63% to 49.37%
Learn more here: brainly.com/question/17042789
Answer:
8
Step-by-step explanation:
First, divide 32 and 8
32/8=4
Now, multiply 4 and 2
4x2=8
(Hope this helps!)
