Hi student, let me help you out! :)
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We are asked to find the two integers, given that they are consecutive, and their sum is 65.

- Consecutive integers are right next to each other, like 12 and 13. or 65 and 66.
Let the first integer be x, and let the second integer be x+1.
Their sum is 65. Let's set up our equation:

Combine like terms:

Subtract 1 from both sides of the equal sign:

Divide both sides by 2:

To find the second integer, subtract the first integer from the sum of the two integers:


The integers are: 33 and 32.
Hope it helps you out! :D
Ask in comments if any queries arise.
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Answer:
64
Step-by-step explanation:
the expression is
x² - 16x + _
the constant term is the square of the number residing with x divided by 2
the number number x = 16
therefore the constant term is (16/ 2)²
= 8²
= 64
the formula being used here is
(x + a)² = x² + 2ax + a²
I’m not 100% certain but i’m pretty sure 1:3 works