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amid [387]
2 years ago
9

EDA kite is flying at an angle of elevation of approximately 50°. All of the string, 60 m, has been

Mathematics
1 answer:
VashaNatasha [74]2 years ago
7 0

Answer:

The height of the kite to the nearest meter is 46 meters.

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Danny made a mistake in the following problem.
mixas84 [53]
Line 3
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6+n-3×6÷9 when n=2<br> this is a mathematical problem
Len [333]

Answer:

6

Step-by-step explanation:

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2 years ago
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heyyy i did question A but im stuck on question b so if you could help i would really appreciate it it is an emergency &lt;3
stellarik [79]

Answer:

86 cm²

Step-by-step explanation:

Ok, so since 4 circles fit in the square, each circle's diameter must be 10.

Which means the radius of each circle is 5 because 10 ÷ 2 = 5.

Now we can solve for area.

A = πr²

A = 3.14 x 5²

A = 3.14 x 25

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78.5 x 4 = 314 cm²

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2 years ago
Jaidee and Kim are selling fruit for a school fundraiser.
tamaranim1 [39]
What is the rest of the question?
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3 years ago
Determine whether the set of vectors <img src="https://tex.z-dn.net/?f=%20v_%7B1%3D%283%2C2%2C1%29%2C%20v_%7B2%7D%20%3D%28-1%2C-
Korolek [52]
Since each vector is a member of \mathbb R^3, the vectors will span \mathbb R^3 if they form a basis for \mathbb R^3, which requires that they be linearly independent of one another.

To show this, you have to establish that the only linear combination of the three vectors c_1\mathbf v_1+c_2\mathbf v_2+c_3\mathbf v_3 that gives the zero vector \mathbf0 occurs for scalars c_1=c_2=c_3=0.

c_1\begin{bmatrix}3\\2\\1\end{bmatrix}+c_2\begin{bmatrix}-1\\-2\\-4\end{bmatrix}+c_3\begin{bmatrix}1\\1\\-1\end{bmatrix}=(0,0,0)\iff\begin{bmatrix}3&-1&1\\2&-2&1\\1&-4&-1\end{bmatrix}\begin{bmatrix}c_1\\c_2\\c_3\end{bmatrix}=\begin{bmatrix}0\\0\\0\end{bmatrix}

Solving this, you'll find that c_1=c_2=c_3=0, so the vectors are indeed linearly independent, thus forming a basis for \mathbb R^3 and therefore they must span \mathbb R^3.
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2 years ago
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