How to use techniques of adding the additive inverse and multiplying by the Students use algebra to solve equations (of the form px + q = r and p(x + q) = r where p pay with a $10 bill and receive no change, then how much did each bottle of a. If Allen buys 4 uniform shirts at one time, he gets a $10 discount so that the
Starting with x=1, subtract 1 from each side,
(x-1)=0
Our polynomial will have multiplicity of 2 for this particular zero,
(x-1)(x-1)
and do similar with the x=-4, add 4 to each side,
(x+4)=0
So our final result is: (x-1)(x-1)(x+4)
Expand out the brackets if you need this in standard form.
I think it would be no because it has the same number 0 in the input and output side which is a big no no
You can use a calculator online you know? It is 21.3
11 by 16
Explanation:
Set up two equations
2
x
+
2
y
=
54
x
×
y
=
176
Solving the first equation for x
2
x
+
2
y
−
2
y
=
54
−
2
y
this gives
2
x
=
54
−
2
y
Divide both sides by 2
(
2
x
2
)
=
54
−
2
y
2
This gives.
x
=
27
−
y
putting this value into the second equation gives.
(
27
−
y
)
×
y
=
176
multiplying across the parenthesis gives
27
y
−
y
2
=
176
subtracting 176 from both sides gives
is
27
y
−
y
2
−
176
=
0
multiplying by negative one gives
−
27
y
+
y
2
+
176
=
0
factoring this into y gives
(
y
−
11
)
×
(
y
−
16
)
=
0
Solving for both y's gives
y
=
11
,
y
=
16
