<span>To find the answers to each you have to divide the total distance by the total time to get the answer in meters/sec, which would be distance run per sec.
A. 200m/19.30sec = 10.36 meters per second
B. 400m/43.18sec = 9.26 meters per second
C. 100m/9.69sec = 10.32 meters per second</span>
Answer:
y=(0.1)x and y=2(1/4)x represent exponential decay
the rest all are an equation used for exponential growth
Answer:
This is
of your money.
Step-by-step explanation:
We have a decimal number, and we want the answer to be a fraction. To transform a decimal number into a fraction, we multiply both the numerator and the denominator by 10 until none of them have decimal parts. So

This is
of your money.
Answer: Hello!
the cross product between sets is defined as:
if A = {a,b,c} and B = {1,2,3)
then
![AxB = \left[\begin{array}{ccc}a\\b\\c\end{array}\right]x\left[\begin{array}{ccc}1&2&3\end{array}\right] =\left[\begin{array}{ccc}a1&a2&a3\\b1&b2&b3\\b1&b2&b3\end{array}\right]](https://tex.z-dn.net/?f=AxB%20%3D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%5C%5Cb%5C%5Cc%5Cend%7Barray%7D%5Cright%5Dx%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5Cend%7Barray%7D%5Cright%5D%20%20%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da1%26a2%26a3%5C%5Cb1%26b2%26b3%5C%5Cb1%26b2%26b3%5Cend%7Barray%7D%5Cright%5D)
where the A took the place of the columns, and B for the files.
then if our sets are A = {a,b} and B = {a,b,c)
a) AxB
![AxB = \left[\begin{array}{ccc}aa&ab&ac\\ba&bb&bc\end{array}\right]](https://tex.z-dn.net/?f=AxB%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Daa%26ab%26ac%5C%5Cba%26bb%26bc%5Cend%7Barray%7D%5Cright%5D)
b) BxA
![BxA = \left[\begin{array}{ccc}aa&ab\\ba&bb\\ca&cb\end{array}\right]](https://tex.z-dn.net/?f=BxA%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Daa%26ab%5C%5Cba%26bb%5C%5Cca%26cb%5Cend%7Barray%7D%5Cright%5D)
c) AxA
![AxA = \left[\begin{array}{ccc}aa&ab\\ba&bb\end{array}\right]](https://tex.z-dn.net/?f=AxA%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Daa%26ab%5C%5Cba%26bb%5Cend%7Barray%7D%5Cright%5D)
d) BxB
![BxB = \left[\begin{array}{ccc}aa&ab&ac\\ba&bb&bc\\ca&cb&cc\end{array}\right]](https://tex.z-dn.net/?f=BxB%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Daa%26ab%26ac%5C%5Cba%26bb%26bc%5C%5Cca%26cb%26cc%5Cend%7Barray%7D%5Cright%5D)
Hope it helps, i know that is kinda hard work with this kind of operations, i tried to make a kinda of map in the first part so you can replace the values of A and B and do the multiplications by yourself, if you have troubles don't doubt of asking.
Answer:
the answer is D. 38.15
Step-by-step explanation:
the lunch meat is 5.50 for 5lbs. She only needs 2 1/2 lbs so you would just divide 5.50 by 2 (because 2 1/2 is half of 5). for the soft drinks, it is 9.99 for 3 so each one 3.33 (divide 9.99 by 3). When you add two more to get five cases in total, you get 16.65 (because 9.99 plus 3.33 plus 3.33 = 16.65). the lunch meat is 4.25 each and you need 3 so you just multiply 4.25 by 3. the snack mix bags are 2 for 1.50 each. that means that two is 3.00. you need four so you just do 3.00+3.00 which equals 6. when you add these totals together, you get 38.15