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LuckyWell [14K]
3 years ago
13

Randy wants to attach a 16 16 foot string of lights to the top of the 15 15 foot mast of his sailboat. How far from the base of

the mast should he attach the end of the light string? Round your answer to two decimal places.
Mathematics
1 answer:
Vladimir79 [104]3 years ago
3 0

Answer:

5.57 feet

Step-by-step explanation:

In this problem, the light string, the height of the mast and the distance between the base of the mast and the end of the string form a right triangle, in which:

- The hypothenuse is the string

- The height is the mast

- The base is the distance between the base of the mast and the end of the light string

Here in this problem, we have:

L=16 ft (length of the string, hypothenuse)

h=15 ft (height of the mast, height)

So we can find the distance between the base of the mast and the end of the string just by applying Pythagorean's theorem:

d=\sqrt{L^2-h^2}=\sqrt{16^2-15^2}=5.57 ft

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How to round 70 to the nerest 100
den301095 [7]

Answer:

100

Step-by-step explanation:

First, you look at wether the first digit in this case is above or below a 5. Since it is, you would round up. The closest hundred to this number is 100, so that is the answer. For 3 digit numbers or higher, look at the tens place to determine the nearest hundred. Same rule applies for rounding up or down.

Hope I helped :)

6 0
3 years ago
You have an above ground pool that is 20 feet in diameter. One bag of sand does three square feet. How many bags of sand do you
r-ruslan [8.4K]

Answer:    Number of sand bags are 105

Step-by-step explanation:

Alright, lets get started.

The diameter of pool is given as : 20 \ \text{feet}

The radius of pool will be : r=\frac{20}{2}=10

So the area of the pool will be:

Area = \pi r^2

Area = \pi *10^2

Area = 100 \pi

Area = 314.16

3 square feet is covered by 1 sand bag, so

314.16 square feet will be covered by : \frac{314.16}{3}

So, no of sand bag = 104.7

Rounding off to nearest number

Number of sand bags are 105  :   Answer

Hope it will help :)

8 0
4 years ago
What is the unit rate for 1 box and 30 pounds​
Ksivusya [100]

Set up the equation.

We want a unit rate where 1 is in the denominator, so we divide top and bottom by 30.

1/30

Divide 30 on each side of 1/30

0.033333 box / 1 pound

Therefore you have 0.033333 box per one pound.

Thanks for usinm Brainly :)

7 0
4 years ago
Billy wrote this question to represent the total number of apples he has in two baskets 25=12+a
dexar [7]

25 = 12 + a
- 12 \:  \:  \:   - 12
13 = a

3 0
3 years ago
Read 2 more answers
The scores on a Psychology exam were normally distributed with a mean of 67 and a standard deviation of 8. Create a normal distr
Trava [24]

Answer:

(a) The percentage of the scores were less than 59% is 16%.

(b) The percentage of the scores were over 83% is 2%.

(c) The number of students who received a score over 75% is 26.

Step-by-step explanation:

Let the random variable <em>X</em> represent the scores on a Psychology exam.

The random variable <em>X</em> follows a Normal distribution with mean, <em>μ</em> = 67 and standard deviation, <em>σ</em> = 8.

Assume that the maximum score is 100.

(a)

Compute the probability of the scores that were less than 59% as follows:

P(X

                =P(Z

*Use a <em>z</em>-table.

Thus, the percentage of the scores were less than 59% is 16%.

(b)

Compute the probability of the scores that were over 83% as follows:

P(X>83)=P(\frac{X-\mu}{\sigma}>\frac{83-67}{8})

                =P(Z>2)\\\\=1-P(Z

*Use a <em>z</em>-table.

Thus, the percentage of the scores were over 83% is 2%.

(c)

It is provided <em>n</em> = 160 students took the exam.

Compute the probability of the scores that were over 75% as follows:

P(X>75)=P(\frac{X-\mu}{\sigma}>\frac{75-67}{8})

                =P(Z>1)\\\\=1-P(Z

The percentage of students who received a score over 75% is 16%.

Compute the number of students who received a score over 75% as follows:

\text{Number of Students}=0.16\times 160=25.6\approx 26

Thus, the number of students who received a score over 75% is 26.

5 0
4 years ago
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