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Crank
3 years ago
5

How to round 70 to the nerest 100

Mathematics
1 answer:
den301095 [7]3 years ago
6 0

Answer:

100

Step-by-step explanation:

First, you look at wether the first digit in this case is above or below a 5. Since it is, you would round up. The closest hundred to this number is 100, so that is the answer. For 3 digit numbers or higher, look at the tens place to determine the nearest hundred. Same rule applies for rounding up or down.

Hope I helped :)

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Answer:

Answer = $30.00 advanced and $36.00 same day.

Step-by-step explanation: We can replace 20:40 ratio.

30 x 20 and 70 x 20 = 600+ 800 =3/5  to find 2/4 = 12/20 finds 10/20 through HCF and hereafter we have one ticket is 1/6 more. So if 60 tickets were sold for 2000 then $33.33 would be the average and if one was 1/6 more than the other it is 0.5/6 higher than 33.33 =2.66 more = £36 for All day and £30 for Advanced tickets. 36 x 20 = $600  and 36 x 40 =$1400. We know its $30 as we can double check its ratio after. 20:40 is 1/2 but then take off $3 each side to balance back to find $60 combined. $2000=1400+$600 =1:2 and 2:4 ratio.

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2 years ago
A pyramid has cross-sectional, taken parallel to its base that are?
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3 years ago
What is 10.5 as a mixed number
NeTakaya
10 1/2

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4 0
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A number is multiplied by 4, and then 6 is added to the product. The result is 18. What is the number? I already know that the a
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4 0
3 years ago
Jeremiah plans on building a 5 meter long garden walkway that is paved with square stones that measure LaTeX: \frac{5}{6}5 6 met
yan [13]

Answer:

Example 1

A backyard farmer wants to enclose a rectangular space for a new garden. She has purchased 80 feet of wire fencing to enclose 3 sides, and will put the 4th side against the backyard fence. Find a formula for the area enclosed by the fence if the sides of fencing perpendicular to the existing fence have length

L.

In a scenario like this involving geometry, it is often helpful to draw a picture. It might also be helpful to introduce a temporary variable,

W, to represent the side of fencing parallel to the 4th side or backyard fence.

Since we know we only have 80 feet of fence available, we know that

L + W + L = 80, or more simply, 2L + W = 80. This allows us to represent the width, W, in terms of L: W = 80 – 2L

Now we are ready to write an equation for the area the fence encloses. We know the area of a rectangle is length multiplied by width, so

A = LW = L(80 – 2L)

A(L) = 80L – 2L2

This formula represents the area of the fence in terms of the variable length

L.

Example 2

Returning to our backyard farmer from the beginning of the section, what dimensions should she make her garden to maximize the enclosed area?

Earlier we determined the area she could enclose with 80 feet of fencing on three sides was given by the equation

A(L) = 80L – 2L2. Notice that quadratic has been vertically reflected, since the coefficient on the squared term is negative, so the graph will open downwards, and the vertex will be a maximum value for the area.

In finding the vertex, we take care since the equation is not written in standard polynomial form with decreasing powers. But we know that

a is the coefficient on the squared term, so a = -2, b = 80, and c = 0.

Finding the vertex:

h

=

−

80

2

(

−

2

)

=

20

,

k

=

A

(

20

)

=

80

(

20

)

−

2

(

20

)

2

=

800

The maximum value of the function is an area of 800 square feet, which occurs when

L = 20 feet. When the shorter sides are 20 feet, that leaves 40 feet of fencing for the longer side. To maximize the area, she should enclose the garden so the two shorter sides have length 20 feet, and the longer side parallel to the existing fence has length 40 feet.

Example 3

A ball is thrown upwards from the top of a 40 foot high building at a speed of 80 feet per second. The ball’s height above ground can be modeled by the equation

H(t) = –16t2 + 80t + 40.

What is the maximum height of the ball?

When does the ball hit the ground?

To find the maximum height of the ball, we would need to know the vertex of the quadratic.

h

=

−

80

2

(

−

16

)

=

80

32

=

5

2

,

k

=

H

(

5

2

)

=

−

16

(

5

2

)

2

+

80

(

5

2

)

+

40

=

140

The ball reaches a maximum height of 140 feet after 2.5 seconds.

To find when the ball hits the ground, we need to determine when the height is zero—when

H(t) = 0. While we could do this using the transformation form of the quadratic, we can also use the quadratic formula:

t

=

−

80

±

√

80

2

−

4

(

−

16

)

(

40

)

2

(

−

16

)

=

−

80

s

q

r

t

8960

−

32

Since the square root does not simplify nicely, we can use a calculator to approximate the values of the solutions:

t

=

−

80

−

s

q

r

t

8960

−

32

a

p

p

r

o

x

5.458

The second answer is outside the reasonable domain of our model, so we conclude the ball will hit the ground after about 5.458 seconds.Step-by-step explanation:

8 0
3 years ago
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