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2 years ago

7

U should donate to khan academy: )

1 answer:

Ulleksa [173]2 years ago

7 0

Answer:

We will be donating to Khan to help more and more students learn.

Sincerely Student team at Adams HS, MI

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Factor completely 8x2 − 4x − 84. 4(2x − 3)(x 7) 4(2x 3)(x − 7) 4(x − 3)(2x 7) 4(x 3)(2x − 7).

gizmo_the_mogwai [7]

The factor of the given equation $8x^{2} -4x-84$ will be $4(x+3)(2x-7)$

<h3>What will be the factor of the given equation?</h3>

Given equation is $8x^{2} -4x-84$

Now taking 2 commons from the equation

$4(2x^{2} -x-21)$

now splitting the equation we get

$4(2x^{2} +6x-7x-21)$

$4(2x(x+3)-7(x+3))$

$4(x+3)(2x-7)$

Thus the factor of the given equation $8x^{2} -4x-84$ will be

$4(x+3)(2x-7)$

To know more about Factors of quadratic equation follow

brainly.com/question/1214333

7 0

2 years ago

If you made a graph to represent a situation where each avocado costs $0.89, what would be the slope of the line?

tatuchka [14]

Y=.89x
X- amount of avocados
Y- $total of avocados
.89- for each or 89/100 every avocados

7 0

3 years ago

Do all digits in number 333 have the same value

postnew [5]

No. the first 3 is 300, the second 3 is 30, and the third 3 is 3

6 0

1 year ago

Read 2 more answers

Find the 12th term of the geometric sequence 5, -25, 125, ...5,−25,125,...

katovenus [111]

Answer:

$a_{12}=-244140625$

Step-by-step explanation:

Considering the geometric sequence

$5,-25,\:125,\:...$

$a_1=5$

As the common ratio ' $r$ ' between consecutive terms is constant.

$\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{a_{n+1}}{a_n}$

$r=\frac{-25}{5}=-5$

$r=\frac{125}{-25}=-5$

The general term of a geometric sequence is given by the formula:

$a_n=a_1\cdot \:r^{n-1}$

where $a_1$ is the initial term and $r$ the common ratio.

Putting $n = 12$ , $r = -5$ and $a_1=5$ in the general term of a geometric sequence to determine the 12th term of the sequence.

$a_n=a_1\cdot \:r^{n-1}$

$a_n=5\left(-5\right)^{n-1}$

$a_{12}=5\left(-5\right)^{12-1}$

$=5\left(-5^{11}\right)$

$\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a$

$=-5\cdot \:5^{11}$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}$

$=-5^{1+11}$ ∵ $5\cdot \:5^{11}=\:5^{1+11}$

$=-244140625$

Therefore,

$a_{12}=-244140625$

6 0

3 years ago

Help!!!!!!<br> Please and thank you

fenix001 [56]

Answer:

1. A

2. B

3. A

Step-by-step explanation:

Hope this helps!

5 0

2 years ago