You have to solve for y
Subtract 2x to the other side
Divide both sides by 4
y=-1x/2-2
Graph D has a slope of -1/2 and a y-intercept of -2
I believe it is 269.5 pi cm^3
For part a: you just need to find how far the vertex has been moved from the origin, or the point (0,0). As the vertex is at the point (2,-3), it has been translated right 2 horizontally and down 3 vertically.
For part b: you use the info found in part a to create the equation in the form of y=A(x-h)^2+k. In this case, A =1, so you can ignore it. The h value is the horizontal distance the vertex has been moved. Since it has been moved right 2, this part of the equation would be (x-2). I know it seems like it should be plus 2, but values in parentheses come out opposite. For the k value, find the vertical shift, which is down3, or -3.
Now that you have h and k, substitute them back into the equation.
Your final answer for part b is: y=(x-2)^2 -3.
Answer:
2. is the correct one
Step-by-step explanation:
4x-3x^3+2
Answer:
f(x)=(x+1)^2-2 is the minimum and g(x)=-(x-2)^2+1 is the maximum
Step-by-step explanation:
Looking at the graph, (you should be able to graph this) the parabola for f(x)=(x+1)^2-2 is pointing downwards and stops at the vertex. This vertex is negative which is the lowest point possible which makes it the minimum. The parabola for -(x-2)^2+1 is pointing upwards and stops at the vertex which is the highest point possible which makes it the maximum.