Find the length and width A= 20 cm2 P= 18cm
1 answer:
Answer:
The length is 5 cm and the width is 4 cm
Step-by-step explanation:
I assume that is a rectangle
Let
x----> the length of rectangle
y ---> the width of rectangle
we know that
The area of rectangle is
A=xy
A=20 cm²
so
20=xy -----> equation A
The perimeter of rectangle is
P=2(x+y)
P=18 cm
so
18=2(x+y)
9=x+y -----> y=9-x ----> equation B
Substitute equation B in equation A and solve for x
20=x(9-x)
20=9x-x²
x²-9x+20=0
Solve the quadratic equation by graphing
The solution is x=5 cm (I assume that the length is greater than the width)
see the attached figure
Find the value of y
y=9-5=4 cm
therefore
The length is 5 cm
The width is 4 cm
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Answer:
<h2>17/35</h2>Step-by-step explanation:
We need to get all the fractions with a common denominator before we can solve the problem.
The only fractions that have a common multiple are 1/7 and 3/21, so we'll add these first and then add 1/5.
1/7 = 3/21
Add
6/21 = 30/105
1/5 = 21/105
Simplify
I'm always happy to help :)