X+5=13+3x
Okay. First subtract 5 from both sides.
x + 5 = 13 + 3x
-5 -5
___ __
0 8
x = 8 +3x
Subtract 3x on both sides. (The 3x's get cancelled on the right side.)
x -3x = 8
-2x=8
Divide -2 on each side.
-2x 8
___ = ___
-2 -2
x=-4
Answer:
(2,3)
Step-by-step explanation:
Because both equations involve the y-term -4y, elimination by addition/subtraction is a good choice as we solve this system of linear equations.
Multiply the 1st equation by -1, obtaining -x + 4y = 10; then add the 2nd equation to this result:
-x + 4y = 10
2x - 4y = -8
-------------------
x = 2
Next, find y. Substitute 2 for x in the first equation: 2 - 4y = -10. Subtract 2 from both sides, obtaining -4y = -12. Then y = 3.
The solution is (2,3).
Answer:
The slope to the given points A at (2,6) and B at (4,10) is 2
Therefore slope m=2
Step-by-step explanation:
Given points are A at (2,6) and B at (4,10)
To find the slope of the given two points :
Let
be the given points A at (2,6) and B at (4,10) respectively
Slope m![=\frac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=%3D%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D)
Now substitute the points in the above equation we get
m![=\frac{10-6}{4-2}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B10-6%7D%7B4-2%7D)
![=\frac{4}{2}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B4%7D%7B2%7D)
![=2](https://tex.z-dn.net/?f=%3D2)
Therefore m=2
The slope to the given points A at (2,6) and B at (4,10) is 2
Therefore slope m=2
The answer is D, hope this helps!
6x^2 - x - 40 =(<span>3x - 8)(2x + 5)
and
</span><span>5 + 2x = 2x + 5
</span><span>
so
</span>(6x^2 - x - 40)<span>÷ (5 + 2x)
= [</span>(3x - 8)(2x + 5)] ÷ (5 + 2x)
= 3x -8
answer
3x - 8