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Pie
3 years ago
5

How do you do this ?

Mathematics
1 answer:
jeka57 [31]3 years ago
4 0

Answer: 3(x^2 + 4)/(x - 5)(x + 4)

Step-by-step explanation:

To simplify, begin with 3x^2 + 12 by dividing by 3 first: 3(x^2 + 4)

x^2 - x - 20 can be simplified into (x - 5) (x + 4). To find these terms, you have to figure out what two numbers multiply together to equal -20 but also add to -1.

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If a town with a population of 10.000 doubles in size every 17 years, what will the population​
Aleksandr-060686 [28]

Answer:

20,000

Step-by-step explanation:

10,000 times 2 since it is doubled

7 0
2 years ago
(y − 1)(y + 10)(y-6) < 0
Aliun [14]

Solve for y by simplifying both sides of the inequality, then isolating the variable.

Inequality Form:

y<−10 or 1<y<6

Interval Notation:

(−∞,−10)∪(1,6)

7 0
1 year ago
mrs. warburton weighs her suitcases ready for holiday.It weighs 7.35kg she takes out shoes that weigh 2.6.How heavy is her suitc
kiruha [24]
So all you need to do is 7.35kg takeaway 2.6kg = 4.75kg

Mrs Warburton's bag now weighs 4.75kg
6 0
3 years ago
Read 2 more answers
Could somebody please answer this?
jok3333 [9.3K]
Here are the resulting percentages:
LEAH = 3.5%
RATHA = 2.3%
ED = 1.8%
CHRIS = 4.2%
MARY = 2.5%

You arrive at this answer by dividing the bonus by the wages

BONUS/WAGE = PERCENTAGE OF BONUS TO WAGE.

Chris had the greatest percentage of wages in his bonus
3 0
3 years ago
A textbook search committee is considering
lora16 [44]

Number of ways to select 3 books from 13 books for adoption is 286 .

<u>Step-by-step explanation:</u>

A Permutation is an ordered Combination. When the order does matter it is a Permutation. There are basically two types of permutation:

  • Repetition is Allowed: such as the lock above. It could be "333".
  • No Repetition: for example the first three people in a running race. You can't be first and second.

Formula is given by:

nC_r= \frac{n!}{r! (n-r)!} , where n is the number of things to choose from,  and we choose r of them,  no repetitions,  order matters. Here , n=13 , r=3.

⇒ 13C_3 = \frac{13!}{3!(13-3)!}

⇒ 13C_3 = \frac{13!}{3!(10)!}

⇒ 13C_3 = \frac{13(12)(11)10!}{3(2)(1)(10)!}

⇒ 13C_3 = 13(2)(11)

⇒ 13 C_3 = 286

∴ Number of ways to select 3 books from 13 books for adoption is 286 .

3 0
3 years ago
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