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drek231 [11]
3 years ago
13

A=1/2h(B+b); A=70, B-6, b=1 solve for h

Mathematics
1 answer:
larisa86 [58]3 years ago
5 0

this should help alil better.

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How were the numbers 1 10 100 and 1000 written by romans?
Arturiano [62]
1 --  I
10 -- X
100 -- C
1000 -- M 
8 0
3 years ago
BRAINEST IF YOU GET THSI RIGHT
Scorpion4ik [409]
<h3>Solution :</h3>

\sf \dfrac{6x+4}{3} = \dfrac{5x-5}{8}

By cross multiply, we get

\sf : \implies (6x+4) \times 8 = (5x-5) \times 3

\sf : \implies 48x+32 = 15x-15

\sf : \implies 48x+32 - 15x + 15= 0

\sf : \implies 33x + 47 = 0

\sf : \implies 33x = -47

\sf : \implies x = \dfrac{- 47}{33}

Therefore, answer is \sf x = \dfrac{- 47}{33}

4 0
2 years ago
Read 2 more answers
Is sin theta=5/6, what are the values of cos theta and tan theta?
mina [271]

let's bear in mind that sin(θ) in this case is positive, that happens only in the I and II Quadrants, where the cosine/adjacent are positive and negative respectively.

\bf sin(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{hypotenuse}{6}}\qquad \impliedby \textit{let's find the \underline{adjacent side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{6^2-5^2}=a\implies \pm\sqrt{36-25}\implies \pm \sqrt{11}=a \\\\[-0.35em] ~\dotfill

\bf cos(\theta )=\cfrac{\stackrel{adjacent}{\pm\sqrt{11}}}{\stackrel{hypotenuse}{6}} \\\\\\ tan(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{adjacent}{\pm\sqrt{11}}}\implies \stackrel{\textit{and rationalizing the denominator}~\hfill }{tan(\theta )=\pm\cfrac{5}{\sqrt{11}}\cdot \cfrac{\sqrt{11}}{\sqrt{11}}\implies tan(\theta )=\pm\cfrac{5\sqrt{11}}{11}}

5 0
3 years ago
F(x) = x2 − 8x + 15 g(x) = x − 3 h(x) = f(x) ÷g(x)
olasank [31]
Hello : 
x²-8x+15 = (x-3)(x-5)
<span>h(x) = f(x) ÷g(x) = (x-3)(x-5)/(x-3)= x-5</span>
5 0
3 years ago
Read 2 more answers
HELP ASAP PLZ 15 points!<br> ............
Allisa [31]

Well I would say A because it went from 8 to 38 which is plus ten.

7 0
3 years ago
Read 2 more answers
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