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faust18 [17]
3 years ago
11

a jar contains 6 jellybeans, 4 green jellybeans, and 4 blue jelly beans. if we choose a jellybean, then another without putting

the first one back in the jar, what is the probability that the first jelly bean will be blue, and the second one will be blue as well?
Mathematics
1 answer:
posledela3 years ago
8 0
Probability first one is blue is 4/6+4+4=4/14
the second one is also blue is 4-1/6+4+4-1=3/13

The probability of getting blue both time is 4/14*3/13=12/182=0.0659=6.59%

Answer:
0.0659 or 6.59%
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Please help me thank you
Hoochie [10]

Answer:

\large\boxed{\sin2\theta=\dfrac{\sqrt3}{2},\ \cos2\theta=\dfrac{1}{2}}

Step-by-step explanation:

We know:

\sin2\theta=2\sin\theta\cos\theta\\\\\cos2\theta=\cos^2\theta-\sin^2\thet

We have

\sin\theta=\dfrac{1}{2}

Use \sin^2\theta+\cos^2\theta=1

\left(\dfrac{1}{2}\right)^2+\cos^2\theta=1\\\\\dfrac{1}{4}+\cos^2\theta=1\qquad\text{subtract}\ \dfrac{1}{4}\ \text{from both sides}\\\\\cos^2\theta=\dfrac{4}{4}-\dfrac{1}{4}\\\\\cos^2\theta=\dfrac{3}{4}\to\cos\theta=\pm\sqrt{\dfrac{3}{4}}\to\cos\theta=\pm\dfrac{\sqrt3}{\sqrt4}\to\cos\theta=\pm\dfrac{\sqrt3}{2}\\\\\theta\in[0^o,\ 90^o],\ \text{therefore all functions have positive values or equal 0.}\\\\\cos\theta=\dfrac{\sqrt3}{2}

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3 0
3 years ago
Solve for q: 30 + q=43​
dsp73

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5 0
3 years ago
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