All categories

3 years ago

Which expression is equivalent to 12(2+3x−6) ?

Mathematics

2 answers:

vodomira [7]3 years ago

7 0

I think the answer is C.

alexdok [17]3 years ago

5 0

12(2 + 3x - 6)

simplify the parenthesis

12( 2 - 6 + 3x)
12 (-4 + 3x)

distribute 12 to all monomials inside the parenthesis

-48 + 36x

36x - 48 is your answer

hope this helps

You might be interested in

What’s the slope ? PLS NEED HELP!

yawa3891 [41]

Answer:

m = -1/2

Step-by-step explanation:

m = slope = rise/run

rise +1

run -2

rise/run = 1/-2

-1/2

7 0

3 years ago

What x what = 1600 pls help me

Likurg_2 [28]

Answer:

1600 × 1 = 1600

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Integrate <img src="https://tex.z-dn.net/?f=e%5E%7B4x%7D%5Csqrt%7B1%2Be%5E%7B2x%7D%20%7D%20dx" id="TexFormula1" title="e^{4x}\sq

AnnyKZ [126]

Answer:

$(\frac{(1+e^{2x}) ^{\frac{5}{2} } }{{5}} + \frac{(1+e^{2x} )^{\frac{3}{2} } }{{3}} )+C$

Step-by-step explanation:

Given that the function

f(x) = $e^{4x} \sqrt{1+e^{2x} }$

Now integrating on both sides, we get

$\int\limits{f(x)} \, dx = \int\limits{e^{4x} \sqrt{1+e^{2x} } dx$

= $\int\limits{e^{2x} e^{2x} \sqrt{1+e^{2x} } dx$

Let $1 + e^{2x} = t$

$e^{2x} = t -1$

$2e^{2x}dx = d t$

$e^{2x}dx = \frac{1}{2} d t$

= $\int\limits{( \sqrt{1+e^{2x} }) e^{2x} e^{2x} dx$

= $\int\limits {\sqrt{t}(t-1)\frac{1}{2} dt }$

= $\frac{1}{2} \int\limits {\sqrt{t} (t) -\sqrt{t} ) dt }$

= $\frac{1}{2} \int\limits {(t^{\frac{1}{2} } t^{1} +t^{\frac{1}{2} } ) } \, dx$

$= \frac{1}{2} \int\limits {(t^{\frac{3}{2} } +t^{\frac{1}{2} } ) } \, dx$

= $\frac{1}{2} (\frac{t^{\frac{3}{2} +1} }{\frac{3}{2}+1 } + \frac{t^{\frac{1}{2} +1} }{\frac{1}{2}+1 } )+C$

= $\frac{1}{2} (\frac{t^{\frac{3}{2} +1} }{\frac{5}{2} } + \frac{t^{\frac{1}{2} +1} }{\frac{3}{2} } )+C$

= $\frac{1}{2} (\frac{t^{\frac{5}{2} } }{\frac{5}{2} } + \frac{t^{\frac{3}{2} } }{\frac{3}{2} } )+C$

= $(\frac{(1+e^{2x}) ^{\frac{5}{2} } }{{5}} + \frac{(1+e^{2x} )^{\frac{3}{2} } }{{3}} )+C$

<u><em>Final answer:-</em></u>

= $(\frac{(1+e^{2x}) ^{\frac{5}{2} } }{{5}} + \frac{(1+e^{2x} )^{\frac{3}{2} } }{{3}} )+C$

3 0

3 years ago

Find the surface area of this composite solid.

babunello [35]

Not sure but a guess that the answer is
C. 84 m^2

8 0

4 years ago

Read 2 more answers

Consider the polynomial function.

svp [43]

The number of positive zeros is 1. The number of negative zeros is either 3 or 1.

<h3>Rule of Descartes</h3>

This states that the number of real positive zeros of a polynomial are equal to or less than by an even number the number of sign changes of the coefficients of the polynomial, f(x). Also, the number of real negative zeros of a polynomial are equal to or less than by an even number the number of sign changes of the coefficients of the polynomial, f(-x).

<h3>The positive zero</h3>

Since f(x) = x⁴ + 2x³ - 11x² - 5x - 6

The cofficients are +1, + 2, -11, -5, -6

There is no sign change from + 1 to + 2.

There is a sign change from + 2 to - 11.

There is no sign change from - 11 to - 5.

There is no sign change from -5 to - 6.

Since there is only one sign change, there is 1 positive zero.

<h3>The negative zero</h3>

f(-x) = x⁴ - 2x³ - 11x² + 5x - 6

The cofficients are +1, - 2, -11, +5, -6

There is a sign change from + 1 to - 2.

There is no sign change from - 2 to - 11.

There is a sign change from - 11 to + 5.

There is a sign change from +5 to - 6.

Since there are 3 sign changes, we have 3 or 3 - 2 = 1 negative zeros.

So, the number of positive zeros is 1. The number of negative zeros is either 3 or 1.

Learn more about rule of descartes here:

brainly.com/question/11444977

4 0

2 years ago