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Valentin [98]
4 years ago
14

Which equation correctly applies the distributive property?

Mathematics
1 answer:
natali 33 [55]4 years ago
7 0
<span>distributive property
</span><span>B.​ −3⋅(6.48)=(−3⋅6)+(−3⋅0.4)+(−3⋅0.08) ​</span>
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Residuals
PolarNik [594]

Answer:

  1. predicted attendance: 141.35

  2. residual: 18.65

Step-by-step explanation:

1. Predicted attendance is ...

  y = -5.9·5 +170.85 = 141.35

__

2. As the problem statement tells you, ...

  actual value - predicted value = residual

  160 - 141.35 = 18.65 . . . the residual

6 0
3 years ago
Find the value of 7 + 3^(2) (-5 + 1)-:2
vladimir2022 [97]

Answer:

7+(((3^2)*((-5)+1))/2

=-11

Step-by-step explanation:

3 0
3 years ago
A sequence is defined by an = -5+ (n - 1) 14, where n is a positive integer. What is the value of 410?
Jobisdone [24]

The sequence an = -5 + (n - 1)14 is an arithmetic sequence

The value of a10 is 121

<h3>How to determine the the a10-th term?</h3>

The sequence is given as:

an = -5 + (n - 1)14

To calculate the value of a10, we set n = 10

So, we have:

a10 = -5 + (10 - 1) * 14

Evaluate the difference

a10 = -5 + 9 * 14

Evaluate the product

a10 = -5 + 126

Evaluate the sum

a10 = 121

Hence, the value of a10 is 121

Read more about sequence at:

brainly.com/question/6561461

7 0
2 years ago
Find two unit vectors orthogonal to a=⟨−2,−4,−2⟩a=⟨−2,−4,−2⟩ and b=⟨−3,5,2⟩b=⟨−3,5,2⟩ Enter your answer so that the first non-ze
Levart [38]

Answer:

u₁= ⟨1/(7*√3),−5/(7*√3) ,−11/(7*√3)⟩

u₂= ⟨-1/(7*√3),5/(7*√3) ,11/(7*√3)⟩

Step-by-step explanation:

for  a=⟨−2,−4,−2⟩ and b=⟨−3,5,2⟩

a vector orthogonal to a and b can be found through the vectorial product of a and b. Thus

c= a x bc=\left[\begin{array}{ccc}i&j&k\\-2&-4&-2\\-3&5&2\end{array}\right] =  \left[\begin{array}{ccc}-4&-2\\5&2\end{array}\right]*i+\left[\begin{array}{ccc}-2&-2\\-3&2\end{array}\right]*j+\left[\begin{array}{ccc}-2&-4\\-3&5\end{array}\right]*k = 2*i  -10*j  - 22*k

then c₁=⟨2,−10,−22⟩ and c₂= - c₁= ⟨-2,10,22⟩ are orthogonal to a and b

the corresponding unit vectors are

u₁=c₁/|c₁| = ⟨2,−10,−22⟩ / √(2²+(−10)²+(−22)²) = ⟨2,−10,−22⟩/(14*√3) =  ⟨1/(7*√3),−5/(7*√3) ,−11/(7*√3)⟩

then u₂= - u₁=  ⟨-1/(7*√3),5/(7*√3) ,11/(7*√3)⟩

then the unit vectors are

u₁= ⟨1/(7*√3),−5/(7*√3) ,−11/(7*√3)⟩

u₂= ⟨-1/(7*√3),5/(7*√3) ,11/(7*√3)⟩

7 0
4 years ago
A motorboat goes downstream in river and covers a distance between to coastal towns in 5 hours . It covers this distance upstrea
Radda [10]

Answer:

The speed of the boat in still water is 33 km/h

Step-by-step explanation:

Let us denote the speed of the boat in still water as x km/h.

Thus;

Since the speed of the stream is 3 km/h, then while going downstream, the total speed on the boat would be; (x + 3) km/h

Formula for distance = speed x time

Since we are told that the time taken to cover the distance downstream is 5 hours, then;

Distance covered in 5 hours = 5(x + 3) km

Therefore, distance between A and B is 5(x + 3) km

However, while going upstream the boat will work against the water current.

Therefore, its speed upstream will be (x − 3) km/h.

we are told that the time taken to cover the distance downstream is 6 hours, then;

Distance covered in 6 hours = 6(x − 3) km

Therefore, distance between A and B is 6(x - 3) km

The true distance between A and B has to be the same.

So,

5(x + 3) = 6(x - 3)

This gives;

5x + 15 = 6x - 18

15 + 18 = 6x - 5x

x = 33

Therefore, the speed of the boat in still water is 33 km/h

3 0
3 years ago
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